Answer:
The slope is -4 and the y-intercept is (0,10)
Step-by-step explanation:
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
7/8 and 9/16
7*2/8*2 = 14/16
14/16 and 9/16
Now since we have a common denominator, we can compare the numerators.
14/16 is greater, so 7/8 is greater than 9/16
Answer: 7/8 is bigger
The unknown is the distance in kilometres
The given is the distance in miles=140 miles
1 mile=1.6093km
140 miles=?
140/1*1.6093km=225.302km
Therefore the 140 miles in km is 225.302km
Answer:
(see image)
bottom right image
Explanation:
First try the origin (0,0) to rule out two of the graphs.
3y ≥ x - 9 3(0) ≥ (0) - 9
3 ≥ - 9
yes 3x + y > - 3 3(0) + (0) > - 3
3 > - 3
yes so the origin should be in the shaded area of the graph, which rules out the top right and bottom left graphs.
Now try a coordinate that is in the shaded area of one of the remaining graphs, but not in the other one. If it works, the graph is the one that has that point in the shaded region, and vice versa.
Try point (4, 2)
3y ≥ x - 9
3(2) ≥ (4) - 9
6 ≥ - 5
yes3x + y > - 3
3(4) + (2) > - 3
12 + 2 > - 3
14 > - 3
yesSo the graph is the bottom right one since (4, 2) is included in that shaded region.