Please help me with this problem
1 answer:
9514 1404 393
Answer:
(x, y) = (-3, -13) or (-8, -23)
Step-by-step explanation:
The values for y can be equated and the resulting quadratic solved by factoring.
2x -7 = x^2 +13x +17
0 = x^2 +11x +24 . . . . . . subtract 2x-7
0 = (x +8)(x +3) . . . . . . . .factor*
The values of x that make these factors zero are x=-8 and x=-3. The corresponding values of y are ...
y = 2(-8) -7 = -23
y = 2(-3) -7 = -13
The solutions are ...
(x, y) = (-8, -23) and (-3, -13)
_____
* The constants in the binomial factors are factors of 24 that total 11. You know that ...
24 = 1×24 = 2×12 = 3×8 = 4×6
The sums of these factors are 25, 14, 11, 10. The factors 3 and 8 are the constants in the binomial factors of the quadratic.
"24" is the constant in the quadratic. "11" is the coefficient of the x term.
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Answer:
(1, 3)
Step-by-step explanation:
Given coordinates of 2 endpoints, G(-2, 5) and H(4, 1), midpoint of AB is calculated as shown below:
Midpoint (M) of GH, for G(-2, 5) and H(4, 1) is given as:
Let
Thus:
Coordinates of the midpoint of GH = (1, 3).
Answer:
4cos4x
Step-by-step explanation:
let's use cos
amplitude=4
period=pi/2
2pi/x=pi/2
x=4
no phase shift
y=4cos4x
pic from desmos
