Answer:
red
Explanation:
public class CarTest {
public static void main(String[] argvs) {
//below line will create an object of CarTest class Object
CarTest carTest = new CarTest();
//This will call runDemo method
carTest.runDemo();
}
public void runDemo() {
//Below line will create an object of Car class with color blue and 4 wheel
Car c = new Car("blue", 4);
//Bellow Line will change the color from blue to red, see the logic writteen in chnageColor method definition
changeColor(c, "red");
//Below line will print the color as red
System.out.println(c.getColor());
}
public void changeColor(Car car, String newColor) {
//This line will set the color as passed color in the car object
car.setColor(newColor);
}
}
1)<u> </u><u>An opening conference. The opening conference is a brief meeting during which the OSHA inspector will explain the purpose of the inspection.</u>
2) <u>A worksite “walkaround” The walkaround is the actual inspection.</u>
3) <u>A closing conference.</u>
The Network layer (1) directs date from one LAN to another.
<h2>Option D: a call to a private method of the superclass</h2>
Explanation:
Option a: a method with the "same signature" is allowed in the subclass. There will not be any confusion because the object which is trying to call the method will decide whether to call the sub class or super class.
Option b: a call to a super class constructor is possible because, when you create an object of sub class automatically the super class constructor will be called. Even the sub class constructor can call the super class constructor explicitly.
Option c: A subclass can create method that's not defined by the super class
Option D: a private method is private inside the class and hence even the object of that class cannot access.
