Exhaled air has more carbon dioxide because the blood contains some carbon dioxide (a waste product) that is transferred to the air in the lungs, which is then exhaled. The result is that the exhaled air contains less oxygen and more carbon dioxide than the inhaled air. The air in the lungs also becomes humidified with water before it is exhaled.
Answer:
Phagocytic defense in the normal lung is shared principally by two kinds of cells - alveolar macrophages that reside on the air surface and roam the alveoli and PMNs that circulate in the intravascular space or are stored transiently in areas adjacent to the capillary-alveolar interface (marginated in capillaries)
Explanation:
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The answer is e, as in terms of d, proteins are not sandwiched between the two bilayers, but wedged in the bilayer to selectively let in different molecules. With c, phospholipids do not drift, into the membrane, for it is the membrane itself. With b it is the other way around, the phospholipid bilayer makes up the membrane, and proteins are embedded into it. Lastly, for a, a fluid mosaic model wouldn’t portray phospholipids drifting in the dark phospholipid bilayer, as they are an independent molecule consisting only as the cell membrane. Hope that’s helpful! :)
Answer:
Sarcomere
Explanation:
The muscle fiber / myofibrils consist of 2 types of filaments - actin and myosin. The myosin filaments are thick filament whereas the actin filaments are the thin filament.
In addition to this, the muscles have A-band and I-bands. These bands give the muscles alternate light and dark colour band structure. In the A-band, myosin filaments are present, whereas in the I - band the actin filaments are found.
In I-band 2 Z-lines are located. The area between the Z-lines is called sarcomere. In this sarcomere region both actin and myosin filaments present.
When muscles get contracted the length of the sarcomere shorten. The actin and myosin filaments overlap in this area. A cross-bridge form between them, with the help of filamentous protein titin.
Interphase is important for cell division because it allows the cell to grow, replicate its DNA, and make final preparations for cell division.