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kkurt [141]
3 years ago
10

Explain why the formula is not valid for matrices. Illustrate your argument with examples. (A + B)(A − B) = A2 − B2 The formula

is not valid because in general, the distributive property is not valid for matrices. The formula is not valid because in general, B(−B) ≠ −B2 for matrices. The formula is not valid because in general, AB ≠ BA for matrices. The formula is not valid because in general, A(−B) ≠ −AB for matrices. Select the pair of matrices, A and B, for which the formula is not valid.
Mathematics
1 answer:
julsineya [31]3 years ago
7 0

Answer:

The formula is not valid because the commutative property with respect to the matrix product operation is not fulfilled in the vector space of the real matrices.

Step-by-step explanation:

The formula is not valid because the commutative property with respect to the matrix product operation is not fulfilled in the vector space of the real matrices. That is, AB does not necessarily equal BA.

(A+B)(A-B) = A^2-AB+BA-B^2\neq A^2 - B^2

A=\left[\begin{array}{ccc}1&0&0\\0&0&6\\0&8&0\end{array}\right] \\B=\left[\begin{array}{ccc}0&2&0\\6&0&0\\0&0&9\end{array}\right] \\(A -B) = \left[\begin{array}{ccc}1&-2&0\\-6&0&6\\0&8&-9\end{array}\right]\\\\(A + B) = \left[\begin{array}{ccc}1&2&0\\6&0&6\\0&8&9\end{array}\right]\\(A - B)(A + B) = \left[\begin{array}{ccc}-11&2&-12\\-6&36&54\\48&-72&-33\end{array}\right]\\A^2 - B^2 = \left[\begin{array}{ccc}-11&0&0\\0&36&0\\0&0&-33\end{array}\right]\\

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Given the dartboard of diameter 20in, divided into 20 congruent sectors,

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The area of a circle is given by the formula

A=\pi r^2

A sector of a circle is a fraction of a circle. The fraction is given by \frac{\theta}{360^\circ}. Where \theta is the angle subtended by the sector at the center of the circle.

The formula for computing the area of a sector, given the angle at the center is

A_s=\dfrac{\theta}{360^\circ}\times \pi r^2

<h3>Given information</h3>

We given a circle (the dartboard) with diameter of 20in, divided into 20 equal(or, congruent) sectors

<h3>Part I: Finding the central angle</h3>

To find the central angle, divide 360^\circ by the number of sectors. Let \alpha denote the central angle, then

\alpha=\dfrac{360^\circ}{20}\\\\\alpha=18^\circ

<h3>Part II: Find the fraction of the circle that one sector takes</h3>

The fraction of the circle that one sector takes up is found by dividing the angle a sector takes up by 360^\circ. The angle has already been computed in Part I (the central angle, \alpha). The fraction is

f=\dfrac{\alpha}{360^\circ}\\\\f=\dfrac{18^\circ}{360^\circ}=\dfrac{1}{20}

<h3>Part III: Find the area of one sector to the nearest tenth</h3>

The area of one sector can be gotten by multiplying the fraction gotten from Part II, with the area formula. That is

A_s=f\times \pi r^2\\=\dfrac{1}{20}\times3.14\times\left(\dfrac{20}{2}\right)^2\\\\=\dfrac{1}{20}\times3.14\times10^2=15.7in^2

Learn more about sectors of a circle brainly.com/question/3432053

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This means that:

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