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Y_Kistochka [10]
2 years ago
8

6. A sector of a circle is a region bound by an arc and the two radii that share the arc's endpoints. Suppose you have a dartboa

rd that has a diameter of 20 in and it is divided into 20 congruent sectors. Find the area of one sector.
Part I: Find the central angle. (Hint: A circle has 360 degrees.) (1 point)


Part II: Use your answer from Part I to find the fraction of the circle that one sector will take up. (1 point)


Part III: Use the fractional part from Part II with the area formula to find the area of one sector of the circle to the nearest tenth. (2 points)
Mathematics
1 answer:
Aliun [14]2 years ago
8 0

Given the dartboard of diameter 20in, divided into 20 congruent sectors,

  • The central angle is 18^\circ
  • The fraction of a circle taken up by one sector is \frac{1}{20}
  • The area of one sector is 15.7in^2 to the nearest tenth

The area of a circle is given by the formula

A=\pi r^2

A sector of a circle is a fraction of a circle. The fraction is given by \frac{\theta}{360^\circ}. Where \theta is the angle subtended by the sector at the center of the circle.

The formula for computing the area of a sector, given the angle at the center is

A_s=\dfrac{\theta}{360^\circ}\times \pi r^2

<h3>Given information</h3>

We given a circle (the dartboard) with diameter of 20in, divided into 20 equal(or, congruent) sectors

<h3>Part I: Finding the central angle</h3>

To find the central angle, divide 360^\circ by the number of sectors. Let \alpha denote the central angle, then

\alpha=\dfrac{360^\circ}{20}\\\\\alpha=18^\circ

<h3>Part II: Find the fraction of the circle that one sector takes</h3>

The fraction of the circle that one sector takes up is found by dividing the angle a sector takes up by 360^\circ. The angle has already been computed in Part I (the central angle, \alpha). The fraction is

f=\dfrac{\alpha}{360^\circ}\\\\f=\dfrac{18^\circ}{360^\circ}=\dfrac{1}{20}

<h3>Part III: Find the area of one sector to the nearest tenth</h3>

The area of one sector can be gotten by multiplying the fraction gotten from Part II, with the area formula. That is

A_s=f\times \pi r^2\\=\dfrac{1}{20}\times3.14\times\left(\dfrac{20}{2}\right)^2\\\\=\dfrac{1}{20}\times3.14\times10^2=15.7in^2

Learn more about sectors of a circle brainly.com/question/3432053

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Harlamova29_29 [7]

Answer:

1. Callum = 2; Eilidh = 17; Caitlin's =22.

2. Ewan = 44; tree = 308.

Explanation:

Q1. Callum, Eilidh, and Caitlin

Let x = Callum's age

     y = Eilidh's age

     z = Caitlin's age

We have three conditions.

(1)  x = y - 5

(2) z = y + 15

(3) x + y + z = 31

Step 1. Eliminate one of the variables in two of the equations

Subtract (1) from (2):                      z - x = 20

Rearrange:                 (4)             -x + z = 20

Solve (2) for y:           (5)                     y = z - 15

Substitute into (3):         x +  z - 15  + z = 31

                                 (6) x + 2z             = 46

Step 2. Set up two new equations in two variables

(5)                          -x +   z = 20

(6)                           x + 2z = 46

Add (5) and (6):           3z = 66

Divide each side by 2: z = 22

Step 3. Substitute z into (5)

-x + 22 = 20

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Step 4. Substitute x into (1)

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Add 5 to each side     y = 7

Callum's age is 2; Eilidh's age is 7; Caitlin's age is 22.

Q2. Ewan and the tree

Let x = Ewan's age

      y = tree's age

We have two conditions.

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                                     (2)   x + y = 352

Rearrange (1)                (3) -7x + y =     0

                                     (2)    x + y = 352

Subtract (3) from (2)          8x       = 352

Divide each side by 8         x       =    44

Substitute y into (1)                    y = 7 × 44

                                                  y =   308

Ewan's age is 44; the tree's age is 308.

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Again using the above formula we can write

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