D scanner She can scan the files and email a digital copy.
Answer:An initial condition is an extra bit of information about a differential equation that tells you the value of the function at a particular point. Differential equations with initial conditions are commonly called initial value problems.
The video above uses the example
{
d
y
d
x
=
cos
(
x
)
y
(
0
)
=
−
1
to illustrate a simple initial value problem. Solving the differential equation without the initial condition gives you
y
=
sin
(
x
)
+
C
.
Once you get the general solution, you can use the initial value to find a particular solution which satisfies the problem. In this case, plugging in
0
for
x
and
−
1
for
y
gives us
−
1
=
C
, meaning that the particular solution must be
y
=
sin
(
x
)
−
1
.
So the general way to solve initial value problems is: - First, find the general solution while ignoring the initial condition. - Then, use the initial condition to plug in values and find a particular solution.
Two additional things to keep in mind: First, the initial value doesn't necessarily have to just be
y
-values. Higher-order equations might have an initial value for both
y
and
y
′
, for example.
Second, an initial value problem doesn't always have a unique solution. It's possible for an initial value problem to have multiple solutions, or even no solution at all.
Explanation:
Answer:
User Datagram Protocol (UDP) , transport-layer segment.
Explanation:
The User Datagram Protocol is popularly known as UDP. It is defined as the communication protocol which is used across the internet for any time sensitive transmission like the DNS lookup or the video playback.
The UDP provides a unreliable and connectionless service to a invoking application.
The transport layers on sending side converts the application 
messages which it 
from the 
into a transport layer segment called as the transport layer segments. This is achieved by breaking down the application messages into a smaller chunks and then adding the transport layer header into each chunk so as to create a transport layer segment.
Answer:
A. Multifactor authentication
Explanation:
Multifactor authentication is a security system process that requires a user to verify his or her identity by providing two categories of credentials.
A mobile device user has entered her user ID and password to access an online account, she immediately receives a text message with a unique PIN or One Time Password (OTP) that must be entered before she is granted access to the account. This is an example of a multifactor authentication security method.
Answer:
The answers to 1st question and part 2A is given. However, the 2B is not given complete and thus cannot be answered.
Explanation:
UNION is a keyword used in C Language to have a commonly shared memory that can be used by multiple elements. It is a data-type that allows different data types to use the same shared memory location.
Importance: If you want to minimize the use of memory by sharing it between different datatype variables, then use UNION. For Ex. Let's suppose I want to use 2 variables a and b of type char and int respectively. Now, suppose int takes memory space of 2 bytes and char takes 1 byte then the total amount of memory needed = 2 + 1 = 3 Bytes. But, we want to first make use of a, and once done, we want to declare variable b. We can limit the memory use by declaring a memory space of 2 bytes (max of a and b). First, we can use this space to store the int variable and when done with it, we can use it to store the char variable.
PART 2A
typedef struct{
int partNum;
char partName[25];
} partin;
#define Partin partin
