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Ne4ueva [31]
3 years ago
14

If a: b = 2:3, b: c = 4:3, and c: d = 7: 8, find a: d.

Mathematics
1 answer:
Taya2010 [7]3 years ago
3 0

Answer:

a:d=7:9

Step-by-step explanation:

We have a system with 3 equation:

\frac{a}{b}=\frac{2}{3}\\\frac{b}{c}=\frac{4}{3}\\\frac{c}{d}=\frac{7}{8}

If we multiply all of these equations, then we have:

\frac{a}{b}*\frac{b}{c}*\frac{c}{d}=\frac{2}{3}*\frac{4}{3}*\frac{7}{8}\\\frac{a*b*c}{b*c*d}=\frac{2*4*7}{3*3*8}\\\frac{a}{d}=\frac{56}{72}

If we simplify this fraction dividing by 9, then:

\frac{a}{d}=\frac{56:9}{72:9}=\frac{7}{9}

Therefore, a:d=7:9

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Since the limits on either side do not converge to the same point, the limit does not exist (this is choice C).

2. </span>Using a similar approaching as in #1:
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Although the value at x = 5 matches with the limit when approaching from the right, the limit when approaching from the left doesn't match, so the limit does not exist (choice D).

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The line will represent the graph of the equation y=2.5x-8.

The two points necessary to graph would be (2,-3) and (0,-8).

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