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Daniel [21]
2 years ago
13

I have a circular necklace with $18$ beads on it. All the beads are different. Making two cuts with a pair of scissors, I can di

vide the necklace into two strings of beads. If I want each string to have at least $6$ beads, how many different pairs of strings can I make?
Mathematics
1 answer:
algol132 years ago
3 0

Solution:

There are four general types we can make: (6,12),(7,11),(8,10),(9,9).

First type: (6,12), there are 18 possible ways to choose those 6, which are going to be cut from the necklace: choose a direction to count the beads, and choose a starting position (between 2 beads). There are exactly 18 starting positions, since there are 18 spaces between the beads. One cut is equivalent for a pair we can make.

Second type: (7,11), with the same reasoning, there are 18 possible ways to cut the necklace.

Third type: (8,10), with the same reasoning, there are 18 possible ways to cut the necklace.

Fourth type: (9,9), The same reasoning cannot be applied again, since half of the cuts would be exactly the same as the other half. So there are 9 possible cuts, exactly one or each axis of symmetry for the necklace.

The solution will be the sum these values: 18+18+18+9=63

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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IrinaK [193]

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stiks02 [169]

Answer:

y = -7x + 22

Step-by-step explanation:

Given

(x_1,y_1) = (4,-6)

(x_2,y_2) = (2,8)

Required

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This question will be answered using linear interpolation.

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