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serg [7]
3 years ago
9

Your math class is going to test new digital clinometers by measuring the angle of elevation of a kite you will fly. the kite fl

ies to an angle of 50.2° on 520 feet of string. Assuming the the string is taut, how high is the kite to the nearest foot?
A) 624 ft
B) 400 ft
C) 333 ft
D) 677 ft
​

Mathematics
1 answer:
Neporo4naja [7]3 years ago
7 0

Check the picture below.

make sure your calculator is in Degree mode.

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PLEASE HELP. EIGHTH GRADE MATH.
vampirchik [111]

Answer:

Cant see the picture can you zoom in?

\

Step-by-step explanation:

5 0
2 years ago
A random sample of 300 balls hit into play in college baseball games is taken. For each ball hit into play, it is recorded wheth
AlekseyPX

Answer:

Null hypothesis: There is no relationship between direction of the ball and if it resulted in a hit or an out.

Step-by-step explanation:

In this case, the experiment conducted is to determine whether there is any relationship between the direction of the ball and if it resulted in a hit or an out.

A random sample of 300 balls hit into play in college baseball games is taken. For each ball hit into play, it is recorded whether the ball was hit to the left, center, or right of the field, and whether the ball resulted in a hit or an out.

The regression analysis would be used to determine whether there is any relationship between direction of the ball and if it resulted in a hit or an out.

The hypothesis for the regression analysis is defined as follows:

<em>H</em>₀: There is no relationship between direction of the ball and if it resulted in a hit or an out.

<em>H</em>ₐ: There is a significant relationship between direction of the ball and if it resulted in a hit or an out.

5 0
3 years ago
Lim t^4 - 6 / 2t^2 - 3t + 7
Harman [31]

I think you meant to say

\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}

(as opposed to <em>x</em> approaching 2)

Since both the numerator and denominator are continuous at <em>t</em> = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}

Because these expressions are continuous at <em>t</em> = 2, we can compute the limits by evaluating the limands directly at 2:

\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}

6 0
2 years ago
Select the property of equality used to arrive at the conclusion. If x - 3 = 7, then x = 10
goldenfox [79]
X - 3 = 7
add 3 to both sides
x - 3 + 3 = 7 + 3
x = 10

addition property of equality
4 0
2 years ago
SOS if anyone could help that would be appreciated!!!❤️
Anastaziya [24]

Answer:

See below

Step-by-step explanation:

2e)15-4x=10x+45

Solve:

15-4x=10x+45\\-4x-10x=45-15\\-14x=30\\ \boxed {x=-\dfrac{15}{7}}3(x+1)=21

Check:

15-4 \left(-\dfrac{15}{7} \right)=10\left(-\dfrac{15}{7} \right)+45

15+\dfrac{60}{7} \right)=-\dfrac{150}{7} +45

\dfrac{210}{7}  =30

30=30

3a) 3(x+1)=21

Solve:

3(x+1)=21\\3x+3=21\\3x=18\\x=6

3b) 2+3(x+1)=6x

2+3x+3=6x\\5=3x\\

x=\dfrac{5}{3}

3c) -2(2x-3)=-2

Solve:

-2(2x-3)=-2\\-4x+6=-2\\-4x=-8\\x=2

3 0
2 years ago
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