Answer & Explanation:
<u>a.- Revenues: </u>Increase for 3.2 millions
It will be recognize for the entire order, as it was deliveried entirely within the accounting period.
<u>b.- Earnings: </u> Increase for 1.5 millions
The earnings for the business will be the net between the revenues and expenses.
3.2 revenues - 1.7 expenses = 1.5 earnings
<u>c.- Receivables: </u> Increase for 1.8 millions
It will increase for the unpaid portion ofthe order.
<u>d.- Inventory</u> Decrease for 1.7 millions
It will decrease for the entire cost of the order, as it was within this accounting period both, revenues and the expense related to it, will be recognize.
<u>e.- Cash:</u> Increase for 1.4 millions
It will increase for the amount received from the customer. As it was no payment from the business in the transaction.
In general, business writing should be _____.
a.
Easy to read quickly
Answer:
my individual capabilities in project teamwork include tolerance, respect for difference in values, objectivity
Explanation:
I am strong in certain capabilities because of my ability to think outside. To do this, some of my individual capabilities in project teamwork include tolerance, respect for difference in values, objectivity and avoiding instances of associated with crisis during work and an open policy system.
In the other vein, I would need to develop my weaknesses in the areas of over-tolerance and the useof vogue language when angry.
Answer:
John Inc.'s return on equity for this accounting period is:
B.
26.66 percent
Explanation:
Return or equity is a ratio used to calculate the efficiency of a certain business. It is calculated by dividing the net income on the stockholders' equity. Therefore, in our case, we translate this into 40 000 dollars divided into 150 000. Giving us a result of .26 %. Thus, the correct option is the B. option.
Answer:
t value is 1.495
Explanation:
The null and alternative hypothesis are :
H0 : mu = 1327
ha: mu > 1327
This is a one tailed test
Critical value = 1.771
at 0.05 significance level with df = 14-1 = 13
test statistics:
s = 411.53, n = 14
t = (xbar -mu)/(s/sqrt9n))
= ( 1491.43 - 1327)/(411.53/sqrt(14))
= 1.495
Decision:
Reject H0 if tstat > 1.771
Fail to reject H0
