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Lostsunrise [7]
3 years ago
13

Where does the graph of the function y=tan(x) have asymptotes?

Mathematics
2 answers:
FromTheMoon [43]3 years ago
7 0
The graph<span> of </span>y<span> = </span>tan x has<span> vertical </span>asymptotes<span> at </span>x<span> = π/2 and </span>x<span> = –π/2,. The period of the </span>tangent function is<span> π, vertical </span>asymptotes<span> also occur when </span>x<span> = π/2 + nπ, where n </span>is<span> an integer.</span>
bezimeni [28]3 years ago
6 0

Answer:

the asymptotes of graph y=tan(x) occur at  \frac{pi}{2}+n\pi

Step-by-step explanation:

The graph  of y=tan(x) is shown in figure-1

tan\,x=\frac{sin\,x}{cos\,x}

so, the vertical asymptotes occur when dinominator is zero

cos x = 0

0=cos(\frac{pi}{2}) = cos(\frac{pi}{2}+n\pi)

The vertical asymptotes occur at x=\frac{pi}{2}+n\pi

where n is an integer.

Hence, the asymptotes of graph y=tan(x) occur at  \frac{pi}{2}+n\pi

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The first step in solving this problem is to solve for g(3).

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