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3 years ago

What kind of problem is this

Mathematics

2 answers:

antiseptic1488 [7]3 years ago

8 0

$(x-5y)^2=x^2-2\cdot x\cdot5y+(5y)^2=x^2-10y+25y^2$

Anvisha [2.4K]3 years ago

6 0

Answer:

Step-by-step explanation:

lets say x is one and y is 1. 5 times 1 is five and to the power of 2 thats 25 and minus 1 equals 24

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For each graph below, state whether it represents a function.<br>

UkoKoshka [18]

Graph1-Yes
Graph2-yes
Graph 3- NO
Graph4-yes
Graph5-No
Graph6/No

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2 years ago

Estimate Four over five subtracted by 1/2

Valentin [98]

Answer:

Exact form : 3/10

Decimal form : 0.3

Step-by-step explanation: To subtract fractions, find the LCD (Least Common Denominator) and then combine.

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3 years ago

It took a submarine 3 seconds to drop to 12 feet below sea level from the surface. what is the rate of descent

kotegsom [21]

For everyone 4 feet he drops, 1 second will pass. (for everyone 1 second that goes by, he will be 4 feet lower)
12/3=4

4 0

3 years ago

Please help with this I am completely stuck on it

vaieri [72.5K]

Answer:

$f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4$

Step-by-step explanation:

Given:

The function, $H(x)=\sqrt[3]{6x^{2}-4}$

Solution 1:

Let $f(x)=\sqrt[3]{x}$

If $f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}$ , then,

$\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4$

Solution 2:

Let $f(x)=\sqrt[3]{x-4}$ . Then,

$f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}$

Similarly, there can be many solutions.

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3 years ago

I WILL GIVE BRAINLIEST TO CORRECT ANSWER

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3 years ago