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3 years ago

5

Patrick is packing up his closet because he is moving to a new house.He has 100 belts and 25 pairs of shorts to equally distribu

te into boxes. How many will Patrick need to fill with the greatest number of belts and pairs of shorts without having anything left over?

1 answer:

STatiana [176]3 years ago

4 0

It all depends on how big the boxes are but i would say about 5 or 6 boxes if they are big boxes

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John and Martha are contemplating having children, but John’s brother has galactosemia (an autosomal recessive disease) and Mart

Rina8888 [55]

<h2>Answer:</h2>

$Probability=\frac{1}{24}$

<h2>Step-by-step explanation:</h2>

As the question states,

John's brother has Galactosemia which states that his parents were both the carriers.

Therefore, the chances for the John to have the disease is = 2/3

Now,

Martha's great-grandmother also had the disease that means her children definitely carried the disease means probability of 1.

Now, one of those children married with a person.

So,

Probability for the child to have disease will be = 1/2

Now, again the child's child (Martha) probability for having the disease is = 1/2.

Therefore,

<u>The total probability for Martha's first child to be diagnosed with Galactosemia will be,</u>

$Probability=\frac{2}{3}\times \frac{1}{2}\times \frac{1}{2}\times \frac{1}{4}\\Probability=\frac{1}{24}$

(Here, we assumed that the child has the disease therefore, the probability was taken to be = 1/4.)

<em><u>Hence, the probability for the first child to have Galactosemia is $\frac{1}{24}$ </u></em>

3 0

3 years ago

Find the missing terms in the following sequence 2,4,8,16,30, , , , 186,

ivann1987 [24]

Are you sure it is correct because for each one your just doubling the number. 2+2=4. 4+4=8. 8+8=16. I think its suppose to be 16+16= 32 and so on, but I may be wrong

5 0

3 years ago

A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s

jasenka [17]

Answer:

The minimum score of those who received C's is 67.39.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 73, \sigma = 11$

If 69.5 percent of the students received grades of C or better, what is the minimum score of those who received C's?

This is X when Z has a pvalue of 1-0.695 = 0.305. So it is X when Z = -0.51.

$Z = \frac{X - \mu}{\sigma}$

$-0.51 = \frac{X - 73}{11}$

$X - 73 = -0.51*11$

$X = 67.39$

The minimum score of those who received C's is 67.39.

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3 years ago

Help!!!! f(x)=10x+3 g(x)= -7x-4

Nataly [62]

Answer:

8x+7

Step-by-step explanation:

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3 years ago

Jameel drew circle A and found that the measure of the is 58°. He knows that he can use this measure to determine the measure of

Anestetic [448]

Answer:

There is an incompletion here

"FOUND THAT THE --------- IS 58

Step-by-step explanation:

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3 years ago