All categories

2 years ago

Y=5x-3 input and output

Mathematics

1 answer:

leva [86]2 years ago

6 0

Answer:

y out put x input and 3 is input and as 5 . tell me if you get it right

You might be interested in

Given: ABCD is a rhombus, Perimeter = 20, AC:BD = 4:3 Find: Area of ABCD.

REY [17]

4a=20⇒a=5

we know diagonals are perpendicular. if u look at one of the right triangles, you can see that for hypotenuse to be 5, the legs have to be 4 and 3 to satisfy the given ratio 4:3.

so, diagonals are 8 and 6 as we know that diagonals bisect each other.

Area=8*6/2=24

6 0

3 years ago

Plz help idk what this is even about

AysviL [449]

I think the answer is A.

It's probably wanting you to use pythagorean theorem.

6 0

3 years ago

To create a giant gemstone, sara first made two identical square pyramids that each had a base area of 100 square inches. Then s

inysia [295]

Answer:

8 inches.

Step-by-step explanation:

From the statement we have that they first made two identical square pyramids, each with a base area of 100 square inches.

Ab = s ^ 2 = 100

Therefore each side would be:

s = (100) ^ (1/2)

s = 10

So, side of the square base = 10 inches

Then they tell us that they glued the bases of the pyramids together to form the precious stone. The surface area of the gemstone is 520 square inches, so for a single pyramid it would be:

Ap = 520/2 = 260

For an area of the square pyramid we have the following equation:

Ap = 2 * x * s + s ^ 2

Where x is the height of each triangular surface and s is the side of the square base

Replacing we have:

260 = 2 * x * 10 + 10 ^ 2

20 * x + 100 = 260

20 * x = 160

x = 160/20

x = 8

Therefore, the value of x is 8 inches.

5 0

3 years ago

Consider the function g(x) = 10/x

ss7ja [257]

The correct answers are:
(1) The vertical asymptote is x = 0
(2) The horizontal asymptote is y = 0

Explanation:
(1) To find the vertical asymptote, put the denominator of the rational function equals to zero.

Rational Function = g(x) = $\frac{10}{x}$ 

Denominator = x = 0

Hence the vertical asymptote is x = 0.

(2) To find the horizontal asymptote, check the power of x in numerator against the power of x in denominator as follows:

Given function = g(x) = $\frac{10}{x}$ 

We can write it as:

g(x) = $\frac{10 * x^0}{x^1}$ 

If power of x in numerator is less than the power of x in denomenator, then the horizontal asymptote will be y=0.
If power of x in numerator is equal to the power of x in denomenator, then the horizontal asymptote will be y=(co-efficient in numerator)/(co-efficient in denomenator).
If power of x in numerator is greater than the power of x in denomenator, then there will be no horizontal asymptote.

In above case, 0 < 1, therefore, the horizontal asymptote is y = 0

5 0

3 years ago

Read 2 more answers

Helpppp... I suck at algebra. the question is down below 7x(-3)x(-2)^2

ElenaW [278]

-84x^2 is the answer

5 0

3 years ago

Read 2 more answers