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1 year ago

Y=5x-3 input and output

Mathematics

1 answer:

leva [86]1 year ago

6 0

Answer:

y out put x input and 3 is input and as 5 . tell me if you get it right

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Bret needs 450 packs of paper for next week. He has 284 packs of paper. How many more packs of paper dose bret need?

gulaghasi [49]

Answer:

166 packs

Step-by-step explanation:

Data obtained from the question include:

Total pack of paper needed by Bret 450 packs

Bret currently has = 284 packs

The remaining packs of paper needed by Bret = 450 — 284 = 166 packs

5 0

3 years ago

Read 2 more answers

The half life of a drug in the bloodstream is 18 hours. What fraction of the original drug dose remains in 36 hours? in 72 hours

xxTIMURxx [149]

Answer:

1/4 in 36 hours

1/8 in 72 hours

5 0

2 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

3 years ago

in the following diagrams ABD=y,DBC=x,EFH=y, EFG=x and PQS=SQR=x.write the following in terms of x and y ABC

Leokris [45]

Angles are the space between intersecting lines, and they are measured in degrees or radians

The measure of angle ABC is y + x

<h3>How to determine angle ABC</h3>

The given parameters are:

ABD=y,

DBC=x,

EFH=y,

EFG=x

PQS = SQR = x

To determine the measure of angle ABC, we make use of angle ABD and angle DBC

Note that angle ABD and angle DBC have common vertices at points B and D

So, we have:

ABC = ABD + DBC

Substitute known values

ABC = y + x

Hence, the measure of angle ABC is y + x