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madam [21]
3 years ago
9

Marcus wants to know if students at his school like to sing in the shower. He polled 40 students who were not part of the school

choir. He found that 11 of the surveyed students enjoy singing in the shower. Is there a sampling bias in the situation above? A. No. Marcus selected a random, unbiased sample for his study. B. Yes. Marcus created bias by only polling 40 students. C. Yes. Marcus created bias by excluding students who are in the choir. D. There is not enough information to determine if Marcus selected a biased sample.
Mathematics
1 answer:
telo118 [61]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Step-by-step explanation:

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A local university wanted to understand what students prefer to eat during finals. They asked 1000 students, "Do you prefer chic
olga55 [171]

Answer:

P(\text{Pizza}\ |\ \text{Female})=0.225

Step-by-step explanation:

The two-way frequency table is attached below.

We have to calculate the probability of, a person chosen at random prefers pizza given that they are female, i.e P(\text{Pizza}\ |\ \text{female})

This is a conditional probability.

We know that,

P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}

So,

P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}

From the table,

P(\text{Pizza}\ \cap\ \text{Female)}=\dfrac{119}{1000}

P({\text{Female}})=\dfrac{530}{1000}

Putting the values,

P(\text{Pizza}\ |\ \text{Female})=\dfrac{P(\text{Pizza}\ \cap\ \text{Female)}}{P({\text{Female}})}=\dfrac{\frac{119}{1000}}{\frac{530}{1000}}=0.225

8 0
3 years ago
$11.13-$5.50-$6.12=$10.51; $30- $10.51
MrMuchimi
What is the problem?? I would love to help
3 0
3 years ago
The board of examiners that administers the real estate broker's examination in a certain state found that the mean score on the
Goshia [24]

Answer:

The passing score is 645.2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 553, \sigma = 72

If the board wants to set the passing score so that only the best 10% of all applicants pass, what is the passing score?

This is the value of X when Z has a pvalue of 1-0.1 = 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 553}{72}

X - 553 = 1.28*72

X = 645.2

The passing score is 645.2

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2 years ago
Solve for p in the literal equation 4p + 7r = 4.<br> P =
kiruha [24]

Answer:

p= 1-7r/4

hope this helps

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3 years ago
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