All categories

3 years ago

What is the factorization of the trinomial below?

Mathematics

2 answers:

Andreas93 [3]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

4x² + 28x + 48 ← factor out 4 from each term

= 4(x² + 7x + 12)

To factor the quadratic

Consider the factors of the constant term (+ 12) which sum to give the coefficient of the x- term

The factors are + 4 and + 3, since

4 × 3 = 12 and 4 + 3 = 7, thus

x² + 7x + 12 = (x + 3)(x + 4) and

4x² + 28x + 48 = 4(x + 3)(x + 4) → A

dolphi86 [110]3 years ago

6 0

$4x^2+28x + 48=\\4(x^2+7x+12)=\\4(x^2+3x+4x+12)=\\4(x(x+3)+4(x+3))=\\4(x+3)(x+4)$

You might be interested in

What is 2 2/3 minus 1 1/2

vagabundo [1.1K]

Answer:

1 1/6

Step-by-step explanation:

2 2/3 = 2+2/3

1 1/2 = 1+1/2

So (2 2/3) - (1 1/2)=2+2/3-(1+1/2)=

2+2/3-1-1/2=1+(2/3-1/2)=1+(4-3)/6=1+1/6=

1 1/6

5 0

3 years ago

Read 2 more answers

Help me !!!!!!!!!!!!!!!!!!!!

True [87]

Answer:

0 isnt a number loll

Step-by-step explanation:

6 0

3 years ago

Solve |p + 2| = 10Solve |p + 2| = 10<br><br> {-12}<br> {-8, 8}<br> {-12, 8}

valentinak56 [21]

By definition, we have

$|p+2| = \begin{cases} p+2 &\text{ if } p+2 \geq 0 \\-p-2 &\text{ if } p+2 < 0 \end{cases}$

So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that $p+2\geq 0 \iff p \geq -2$

In this case, the absolute value doesn't do anything: the equation is

$p+2 = 10 \iff p = 10-2 = 8$

We are supposing $p \geq -2$ , so we can accept this solution.

Now, suppose that $p+2 < 0 \iff p < -2$ . Now the sign of the expression is flipped by the absolute value, and the equation becomes

$-p-2 = 10 \iff -p = 12 \iff p = -12$

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0

3 years ago

Given C=n+15, determine the value of C when n=4

puteri [66]

Answer: c=19 and n=4

please mark as brainliest if it helped

6 0

3 years ago

Read 2 more answers

Help pls!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

postnew [5]

Answer?

What do you need help with? :)

5 0

2 years ago