Answer:
b
Step-by-step explanation:
Answer:
20 ton
Step-by-step explanation:
We created a system of two separate equations to answer these questions.
"y" will be the total cost to transport the sugar
"x" will be the amount of sugar transported
Therefore, we have to:
y = 3995 + 225.50 * x
y = 6500 + 100.25 * x
We must establish these equations equal to each other because it asks how much of x is necessary to make the same amount of y, therefore:
3995 + 225.50 * x = 6500 + 100.25 * x
solved we have:
225.50 * x - 100.25 * x = 6500 - 3995
125.25 * x = 2505
x = 2505 / 125.25
x = 20
which means that when the amount of sugar transported is 20 tons, the price is the same
Answer:
$7.74
Step-by-step explanation:
0.75x46=34.5
0.52x63=32.76
34.5+32.76=67.26
75-67.26=7.74
Arithmetic sequence: must have a constant common difference.
3/20-1/10=(3-2)/20=1/20
5/30-3/20=(10-9)/60=1/60
Difference is not constant, so no.
Geometric sequence: must have a common ratio
30/20 / (1/10) = 15
5/30 / (3/20) = 100/90 = 10/9
ratio is not constant, so no.
The answer is (c) neither geometric nor arithmetic
Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
