Sample size, n = 75
Point estimate, p = 52/75 = 0.693
Z at 99.7% confidence interval ≈ 2.96
Population mean interval = p+/- Z*Sqrt [p(1-p)/n]
Substituting;
Population mean interval = 0.693 +/- 2.96*Sqrt [0.693(1-0.693)/75] = 0.693+/-0.158 = (0.535,0.851) or (53.5%,85.1%)
Answer:
0.9375
Step-by-step explanation:
Given the following :
Number of coin tosses = 7
Probability that number of heads obtained will be between 2 and 7 inclusive?
x = 2,3,4,5,6,7
Probability (P) = number of required outcomes / total possible outcomes
For a coin toss = 1 Head (H), 1 tail (T)
P(H) = 1 / 2
P(X) = C(7,x) * (1/2)^7
P(X) = C(7, x) / 0.5^-7
P(X) = [C(7,2) + C(7, 3)+ C(7,4) +C(7,5) + C(7,6) +C(7,7)] / 128
P(X) = (21 + 35 + 35 + 21 + 7 + 1) / 128
P(X) = 120 / 128
P(X) = 0.9375
Answer:
Pattern: subtract 2 from the input to get the output
When the input is 9, the output is 7
When the input is 13, the output is 11
Step-by-step explanation:
» <u>Application + Solution</u>
To find the pattern, we have to look for common things we notice between the input and output.
- After analyzing, we can surely notice that we subtract two from the input each time to get the output because 3 - 2 = 1, 8 - 2 = 6, 15 - 2 = 13, and 20 - 2 = 18.
Now that we realized the pattern, we subtract 2 from 9 and 13.
Answer:
m=-2
entire equation in slop int. form is: 7=-2x+5
To get the answer you would subtract 11% from 100%, getting the answer 89%.
