To get the time taken for Jan and Jo to meet we proceed as follows;
Jan's speed=70 mph
Jo's speed =60 mph
distance between =1170
relative speed=70+60=130
time taken for them to meet will be:
time=(distance)/(relative speed)
=1170/130
=9 hours
the answer is 9 hours
For Scott
- He is at 100km 30 degrees
For Spock
- He is at 110km 62 degrees
So The difference between them is just algebraic subtraction of their positions
- 110km 62°-100km 30°
- (110-100)km (62-30)°
- 10km 32° apart
Answer:
a. Equilateral triangle
b. Quadrilaterals
c. Hexagon
Step-by-step explanation:
You'll need to create two equations and have a 'system of equations' then use direct substitution to turn the equation into one. Whichever equation is easiest to solve for x or y. Solve that one for x or y and plug the result in for the variable in the other equation. Then you will have an equation with only 1 unknown.
First you set and equation for length which is three times width
l=3w
The substitute in the perimeter, p, into the equation for perimeter which is p=2l+2w
88=2l+2w
Then substitute in length, l, with the equation previously created: l=3w
88=2(3w)+2w
Multiply 2 and 3w
88=6w+2w
Combine like terms: 6w+2w
88=8w
Divide to get the value for w
w=11
Since you figure the value for w, 11, you can plug it into the equation for length which is l=3w
l=3(11)
When you do you get
l=33
So the length is 33 and the width is 11
