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Basile [38]
3 years ago
10

Can someone please help!!!

Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

f(1) = 5, f(2) = 8, f(3) = 11

Step-by-step explanation:

Common difference refers to how you get from one value in the sequence to the next.

If f(0) = 2, f(1) = 2 + 3 = 5 etc

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It took the Phillips family 6 hours
Lerok [7]

Answer:

Percentage increase.

Step-by-step explanation:

It took the Phillips family 6 hours to drive to their vacation destination. 2 hours and 42 minutes extra because of traffic.

8 hours 42 minutes

-

6 hours 0 minutes

=

2 hours and 42 minutes

Percentage increase.

8 0
2 years ago
Can u guys help me on this?
Nadusha1986 [10]

Answer:

r = 6 m

Step-by-step explanation:

The circumference of a circle is given by

C = 2 * pi *r

Substitute in what we know

37.68 = 2 * 3.14 * r

37.68 = 6.28 r

Divide each side by 6.28

37.68/6.28 = 6.28 r/6.28

6 = r

7 0
3 years ago
Simplify. <br>1: if y&gt;0<br>2: if y&lt;0<br><img src="https://tex.z-dn.net/?f=1%29%3A%20-15%5Csqrt%7By%5E2%7D%5C%5C2%29%3A%20-
Kruka [31]

In general, √(y²) = |y|, since y can be positive or negative and y² would have the same value either way.

So,

1) if y > 0, then |y| = y, and

-15√(y²) = -15 |y| = -15y

2) if y < 0, then |y| = -y, and

-√(16y²) = -|4y| = -|4| |y| = -4 (-y) = 4y

7 0
2 years ago
To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t
ivolga24 [154]

Answer:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:  

Null hypothesis:\mu \leq 100  

Alternative hypothesis:\mu > 100  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic calculated for this case  t_{calc}= 1.42

The degrees of freedom are given by:

df=n-1=30-1=29  

Now we can find the p value using tha laternative hypothesis and we got:

p_v =P(t_{(29)}>1.42)=0.0831  

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

5 0
3 years ago
Evaluate -2x square y, if x= -3 and y = -1
statuscvo [17]

Answer:

18

Step-by-step explanation:

Write the expression

-2x²y

substitute the real values with x=-3 and y= -1

-2(-3²)×(-1)

-2(9)×(-1)

-18×-1

18

8 0
3 years ago
Read 2 more answers
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