Answer:
f(1) = 5, f(2) = 8, f(3) = 11
Step-by-step explanation:
Common difference refers to how you get from one value in the sequence to the next.
If f(0) = 2, f(1) = 2 + 3 = 5 etc
it would be pp
6
XY = 3x – 1, YZ = 5, and XZ = 5x – 8,
We know that XY + YZ = XZ, so
3x - 1 + 5 = 5x - 8
3x + 4 = 5x - 8
3x + 12 = 5x
12 = 2x
6 = x
is A
Step-by-step explanation
b you n t p
