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nikdorinn [45]
3 years ago
14

Plz help with 6,7,8 and 9

Mathematics
1 answer:
Reil [10]3 years ago
3 0
Grayson's mistake was that he multiplied 4 and 3 and then used the exponent he had to square 3 and then multiply it by 4.

Emily's mistake was that she added 2 to 36 instead of multiplying it by -2

Pat's mistake was that he forget to make y into -2 instead of 2

The right way to do this is 4(3^2)+2(-2)
(3^2)=9 9×4=36 2(-2)=-4 -4+9=5
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Step-by-step explanation:

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Which of the following is equivalent to 2 stretching below? (14-9i)+(2+3i)..​
Flauer [41]

Answer:

(14-9i)+(2+3i) = 16-6i

Step-by-step explanation:

We need to find the equivalent of (14-9i)+(2+3i).

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7 0
3 years ago
Evaluate the integral ∫2−1|x−1|dx
defon

I think you might be referring to the definite integral,

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx

Recall the definition of absolute value:

|x| = \begin{cases}x&\text{if }x\ge0\\-x&\text{if }x

Then |x-1|=x-1 if x\ge1, and |x-1|=1-x is x. So spliting up the integral at <em>x</em> = 1, we have

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \int_{-1}^1(1-x)\,\mathrm dx + \int_1^2(x-1)\,\mathrm dx

The rest is simple:

\displaystyle \int_{-1}^2|x-1|\,\mathrm dx = \left(x-\dfrac{x^2}2\right)\bigg|_{-1}^1 + \left(\dfrac{x^2}2-x\right)\bigg|_1^2 \\\\ = \left(\left(1-\frac12\right)-\left(-1-\frac12\right)\right) + \left(\left(2-2\right)-\left(\frac12-1\right)\right) \\\\ = \boxed{\frac52}

5 0
3 years ago
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