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Tpy6a [65]
3 years ago
9

2 Points

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0
Move constant the right side and change it’s sign 3 x > 13 - 4 , subtract the number 3 x > 9 , divide both sides of the inequality by 3 , x > 3
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Prove that if r is any rational number, then 3r2 − 2r + 4 is rational. The following properties may be used in your proof. Prope
ziro4ka [17]

Given:

Expression is

3r^2-2r+4

To prove:

If r is any rational number, then 3r^2-2r+4 is rational.

Step-by-step explanation:

Property 1: Every integer is a rational number. It is Theorem 4.3.1.

Property 2: The sum of any two rational numbers is rational. It is Theorem 4.3.2.

Property 3: The product of any two rational numbers is rational. It is Exercise 15 in Section 4.3.  

Let r be any rational number.

We have,

3r^2-2r+4

It can be written as

3(r\times r)-2r+4

Now,

3, -2 and 4 are rational numbers by property 1.

r^2=r\times r is rational by Property 3.

3r^2\text{ and }-2r are rational by Property 3.

3r^2+(-2r)+4 is rational by property 2.

So, 3r^2-2r+4 is rational.

Hence proved.

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