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3 years ago

I need to know how to get the answer

Mathematics

1 answer:

AleksAgata [21]3 years ago

5 0

You got this homie. You set g(x)=0. Then set the smaller x equation (x-2) equal to 0 and solve. X-2=0 ——> add two to both sides x=2. Do the same for the other.

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asambeis [7]

Answer:

n ≥ -1 or n ≤ 3

Combined:

-1 ≤ n ≤ 3

Since the inequalities are ≤, it'll be a closed circle

The closed circle will start AT -1 and another closed circle will end at 3

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2 years ago

Which of the following ratios are equivalent to 60%?

Murrr4er [49]

Answer:

A. 15:25 & C. 3:5 would be the ratios that are equivalent to 60%

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2 years ago

How does substitution help you to solve systems of equations?

kipiarov [429]

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2 years ago

Daniel created an intersection with his race track. One of the angles at the intersection is 55°. What are the three other angle

melomori [17]

Answer:

55, 125 and 125

Step-by-step explanation:

In this question, we are asked to find the other 3 angles in an intersection.

Please check attachment for what the diagram of the intersection might look like.

The intersection consists simply of 4 angles meeting at a point with the 2 angles on each side vertically opposite to the angles on the other side.

since one of the angles is 55, and we are having a straight line, the other angle would be 180-55 = 125.[ sum of angles on a straight line is 180]

These two angles are vertically opposite, this means that the other three angles are 55,125 and 125.

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3 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago