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Bess [88]
3 years ago
13

At the candy store, Jonathan bought 1.74 pounds of gumdrops, 2.2 pounds of jellybeans, and 1.38 pounds of licorice. How much did

these three items weigh altogether?
Mathematics
2 answers:
adell [148]3 years ago
4 0
The answer is 5.32 lbs
GenaCL600 [577]3 years ago
3 0

Answer:

5.32 lbs

Step-by-step explanation:

add all of them together, this is common sense math you should know how to do this.

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The local office supply store charges $0.08 per page to make photocopies. Lionel paid $20.00 for a set of copies. How many pages
Darina [25.2K]

Answer:

250

Step-by-step explanation:

You do 20/.08 to get 250.

5 0
3 years ago
Read 2 more answers
Evaluate the expression √(-6)/(√(-9) √(-1)) and write the result in the form a+bi.
DaniilM [7]
√6/3√i
Let me know if you need work

3 0
3 years ago
Jim wants to build a rectangular parking lot along a busy street but only has 2 comma 1200 feet of fencing available. If no fenc
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5 0
3 years ago
Q(a+1) - 2q(a) if q(x) = x²+3x+4​
siniylev [52]

q(x) =  {x}^{2} + 3x + 4

_________________________________

Step(1)

To find q(a) we just need to put a instead of x in q(x) function.

Let's do it...

q(a) =  {a}^{2} + 3a + 4

Multiply sides by -2 :

- 2q(a) =  - 2( {a}^{2} + 3a + 4)

- 2q(a) =  - 2 {a}^{2} - 6a - 8

_________________________________

Step (2)

To find q(a+1) we just need to put a+1 instead of x in q(x) function.

Let's do it...

q(a + 1) =  ({a + 1})^{2} + 3(a + 1) + 4 \\

q(a + 1) =  {a}^{2} + 2a + 1 + 3a + 3 + 4 \\

q(a + 1) =  {a}^{2} + 5a + 8

_________________________________

Step (3)

q(a + 1) - 2q(a) =

{a}^{2} + 5a + 8 - 2 {a}^{2} - 6a - 8 =  \\

-  {a}^{2} - a  =  - a(a + 1)

And we're done.

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8 0
4 years ago
Consider the following set of sample data: (34, 32, 34, 32, 40, 37, 31, 31, 29, 27). We're interested in using this data to test
rosijanka [135]

Answer:

Option I and II

Step-by-step explanation:

I. Assuming this represents a random sample from the population, the sample mean is an unbiased estimator of the population mean.

II. Because they're robust, t procedures are justified in this case.

The t procedures are utilized because they are used as a hypothesis testing tool, which allows for testing of an hypothesis applicable to a population where in this case we are testing the null hypothesis about the population mean.

7 0
3 years ago
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