Question

Given a triangle with b = 10, c = 11 , and A = 43°, what is the length of a? Round to the nearest tenth.

Answer 1

Answer:

Option C.

Step-by-step explanation:

Given: b = 10, c = 11 , and A = 43°.

Cosine formula:

$a^2=b^2+c^2-2bc\cos A$

Substitute the given values in the above formula.

$a^2=(10)^2+(11)^2-2(10)(11)\cos (43^\circ)$

$a^2=100+121-220(0.7314)$

$a^2=60.092$

Taking square root on both sides.

$a=\sqrt{60.092}$

$a=7.75619$

$a\approx 7.8$

Hence, the correct option is C.

Answer 2

You are given two sides and an angle.

Using SAS, would use the law of cosines.

a = √(10^2 + 11^2 - 2*10*11*cos(43))

a = 7.75

Round to 7.8