3 years ago

I have a test in the 8th grade its in my language plz help me i need to pass

1 answer:

7 0

I got u it had to work worth the 629 73836

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dezoksy [38]

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hi how are you doing today Jasmine

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3 years ago

Rzqust [24]

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keep it man u will do ok just be careful with other problems

Step-by-step explanation:

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3 years ago

weqwewe [10]

Answer: $(17.14,\ 22.86)$

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

$\overline{x}\pm ME$ , where $\overline{x}$ is the sample mean and ME is the margin of error.

Given : Sample mean: $\overline{x}=20$

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : $ME=2.86$

Now, the confidence interval estimate for the population mean will be :-

$20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)$

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution = $(17.14,\ 22.86)$

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3 years ago

ioda

A.)|−60 − 13| = |−73| = 73 units is the answer

7 0

3 years ago

evablogger [386]

Cosine(angle) = adjacent leg/ hypotenuse

Cosine( angle ) = 18/20

Angle = arccos(18/20)

Angle = 26 degrees

6 0

3 years ago