Must a deciimal divisor and a decimal dividend have the same number of decimal places in order to have a whole number quotient ?

Make a frequency distribution and find the relative frequencies for the following number set. Round the relative frequency to th

Pani-rosa [81]

Solution: We have to find the Frequency and Relative frequency of the given data:

Frequency is the number of times a number occurs.

Relative Frequency is the number of times a number occurs divided by the total number of items.

Therefore, the frequency and relative frequency are calculated as below:

Number Frequency Relative Frequency

20 1 $\frac{1}{31} \times 100 =3.2\%$

21 4 $\frac{4}{31} \times 100 =12.9\%$

22 2 $\frac{2}{31} \times 100 =6.5\%$

23 4 $\frac{4}{31} \times 100 =12.9\%$

24 3 $\frac{3}{31} \times 100 =9.7\%$

25 2 $\frac{2}{31} \times 100 =6.5\%$

26 3 $\frac{3}{31} \times 100 =9.7\%$

27 5 $\frac{5}{31} \times 100 =16.1\%$

28 3 $\frac{3}{31} \times 100 =9.7\%$

29 4 $\frac{4}{31} \times 100 =12.9\%$

Total 31

6 0

3 years ago

Which expression best represents Maria's age if she is 1 3 of her father's age?

Anna71 [15]

Please paste the answer choices next time....
The expression should include a variable for marias age compared to a variable for her fathers

Something like
M=1/3F

M being maria's age and F being her fathers age

5 0

3 years ago

Read 2 more answers

Please solve ILL MARK YOU BRAINIEST!!!!!!!

sweet [91]

Answer:

14. 4 + x - 2

15. 8k - 3k

16. 5 + 2y + 15

Step-by-step explanation:

14. "sum" means adding, "minus" means subtract

sum of four and x: 4 + x

minus two: 4 + x - 2

15. "product" means multiplying, "decreased by" means subtract, "times" means multiply

the product of k and 8: 8k

three times k: 3k

the product of k and 8 decreased by three times k: 8k - 3k

(Depending on what the question is asking, you may or may not need to simplify this to 5k (8k - 3k = 5k))

16. "more" means add, "plus" means add, "twice" means multiply by two

five: 5

plus twice y: 5 + 2y

fifteen more: 5 + 2y + 15

3 0

3 years ago

At homecoming, 125 tickets where sold. Tickets purchased for homecoming cost $20.5 without an activity card, and $15.75 with an

ale4655 [162]

Answer:

Nearly 83 students did not had activity card.

Nearly 42 students had an activity card.

Step-by-step explanation:

Total number of tickets sold at homecoming = 125

Cost of each ticket without activity card = $20.5

Cost of each ticket with activity card = $15.75

Total amount earned = $2365

Let, the number of tickets sold without activity car d = k

So, the number of tickets sold without card = (Total sold - k)

= 125 - k

Now, according to the question:

$20.5(k) + $15.75(125 - k) = $2365

or, 20.5 k + 1968.5 - 15.75 k = 2365

⇒ 4.75 k = 2365 - 1968.5 = 396.5

⇒ $k = \frac{396.5}{4.75 } = 83.47$

Hence, nearly 83 students did not had activity card.

So,the number of students that had activity card = 125 - 83.47 = 41.53 ~ 42

Hence, nearly 42 students had an activity card.

4 0

3 years ago

Twelve less than seven times a number is 16

Murljashka [212]

Are you asking a question? Or would you like this question checked for you?

7 0

3 years ago