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3 years ago

Solve lxl + 7 < 4. {x l x < -11 or x > -3) {x 1-3

Mathematics

1 answer:

uysha [10]3 years ago

5 0

9514 1404 393

Answer:

no solution

Step-by-step explanation:

Subtracting 7 from both sides gives you ...

|x| < -3

The absolute value cannot be negative. There is no solution.

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Graph g is a translation of the graph of y= sin x (dashed line).a) write down the equation of g b) write down the coordinates of

labwork [276]

Answer:

<em>b) The coordinates of P are</em>

<em /> $\displaystyle \left( \frac{3\pi}{2},1\right)$

Step-by-step explanation:

<u>Translation</u>

The dashed line shows the graph of the function

$y = \sin x$

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

Graph G shows the same function but translated by 2 units up, thus the equation of G is:

$\boxed{G(x)= \sin x + 2}$

b) The coordinates of P correspond to the value of

$x = \frac{3\pi}{2}$

The value of G is

$\displaystyle G(\frac{3\pi}{2})= \sin \frac{3\pi}{2} + 2$

Since

$\sin \frac{3\pi}{2}=-1$

$\displaystyle G(\frac{3\pi}{2})= -1+ 2=1$

The coordinates of P are

$\displaystyle \left( \frac{3\pi}{2},1\right)$

8 0

3 years ago

Write the expression in standard form. 2/(2-15i)

Eva8 [605]

<h3>Answer:</h3>

d. 4/229 +30/229i

<h3>Explanation:</h3>

Multiply numerator and denominator by the conjuate of the denominator, then simplify.

$\dfrac{2}{2-15i}=\dfrac{2}{(2-15i)}\cdot\dfrac{(2+15i)}{(2+15i)}=\dfrac{4+30i}{2^2-(15i)^2}\\\\=\dfrac{4+30i}{4+225}=\dfrac{4}{229}+\dfrac{30}{229}i$

6 0

4 years ago

What is da answer?Brainlest to the best answer

zimovet [89]

Answer:

g(-6)=-13

Step-by-step explanation:

$g(x)=3x+5\\\\x=-6\\\\g(-6)=3(-6)+5\\\\g(-6)=-18+5\\\\g(-6)=-13$

when the problem says find g(120) and they give you g(x) you just have to put instead of x put 120

so in this case instead of x we put - 6

6 0

4 years ago

Help me please! <br> I don’t what is the answer?

vovangra [49]

Answer:

see below

Step-by-step explanation:

In order to use ASA congruence, you need to show congruence of angles on either side of a congruent segment. (Angle - Side - Angle) Considering the left side of the figure, you have given that ∠B is congruent to its counterpart, side BC is congruent to its counterpart. So, you need to show the angle at C is congruent to its counterpart. That is, you must show ...

∠BCA ≅ ∠DCE

6 0

4 years ago

Find the value of x when 2(x - 3) + 1 = 3x + 4

Sav [38]

Step 1. Expand

$2x-6+1=3x+4$

Step 2. Simplify $2x-6+1$ to $2x-5$

$2x-5=3x-4$

Step 3. Subtract $2x$ <span> from both sides

</span> $-5=3x+4-2x$

Step 4. Simplify $3x+4-2x$ to $x+4$

$-5=x+4$

Step 5. Subtract 4 from both sides

$-5-4=x$

Step 6. <span>Simplify </span> $-5-4$ to $-9$

$-9=x$

Step 7. Switch sides

$x=-9$

Done! Your answer is $x=-9$

7 0

4 years ago