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Oksanka [162]
4 years ago
12

Which is more, 4 gallons or 18 quarts?

Mathematics
2 answers:
Artyom0805 [142]4 years ago
5 0
There are 4 quarts in a gallon. 4 gallons have 16 quarts , because 4 multiplied by 4 is 16. This means that 18 quarts are more than 4 gallons (16 quarts).
ch4aika [34]4 years ago
5 0
There are more of 18 quartz then gallons because there is 4 quartz in one gallon. So 4 gallons is the same as 4 quartz not 18 quartz
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elixir [45]

Answer:

y = -\frac{1}{4}x

Step-by-step explanation:

1. The slope-intercept form of a linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = slope.

2. To find the slope, let's take the two points (0,0) and (-40,10). After that, let's plug in the values to their corresponding variable in the formula: \frac{y_2-y_1}{x_2-x_1}

  • \frac{10-0}{-40-0}
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3. Since we now know our slope, the equation looks like this so far: y = -\frac{1}{4}x + b.

4. Because b is the y-intercept, b = 0 because the line intersects the y-axis at (0,0).

5. Now that we have the values of m and b, we plug in them to get the equation of: y=-\frac{1}{4}x

3 0
3 years ago
Which equation is represented by the graph below?
garik1379 [7]

Answer:c

Step-by-step explanation:

5 0
3 years ago
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Aleks [24]

Answer:

Option B is correct.

Step-by-step explanation:

We have given a triangle ABC and EDC please look at the figure

We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles

And ∠ACB=∠DCE are vertically opposite angles hence, equal

So, by AA similarity postulate the above to triangles are similar

ΔABC \sim ΔEDC

Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5

NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE

And m∠1 = m∠5 corresponds to m∠EAB=m∠AED

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4 years ago
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Kryger [21]
You have to divide it
4 0
3 years ago
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leonid [27]

Answer:

In five years, the enrollment would have been 10,724 students

Step-by-step explanation:

The general depreciation formula is given as;

P = I( 1 - r)^t

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I is the initial

r is the rate of depreciation = 4.5% = 4.5/100 = 0.045

t is 5 years

substituting these values;

P = 13,500 (1- 0.045)^5

P = 10,723.84

6 0
3 years ago
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