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34kurt
1 year ago
5

What is the solution to y=-2x+7 and y=5x-7

Mathematics
1 answer:
Alexandra [31]1 year ago
4 0

Answer:

x-2,y= 3, it can also be written as (2 ,3)

Step-by-step explanation:

2x-7y=5x-7-2x-7=5x-75x+2x=

7+77x=14x=2y=5x-7=5*2-7=10-..

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Please help with my math
shusha [124]

Answer:

Step-by-step explanation:

These triangles are similar triangles, so there is a number that you can multiply the sides of TUV to find the side lengths of QRS. looking at the triangle, the similar sides are RS being similar to UV and RQ being similar to UT.

If RS~UV, then there is a ratio between them. 54/36=1.5. The ratio is 1.5.

RQ~UT, and by a factor of 1.5, so divide RQ by the scale factor. 24/1.5=16. UT=16=x+5.

x+5=16, subtract 5 from both sides.

x=11

5 0
2 years ago
(50 POINTS) Math Inverse Functions please help
Afina-wow [57]

Answer:

See below.

Step-by-step explanation:

An inverse function has the x and y coordinates switched. For example, if a function has point (1, 3), then the inverse function has point (3, 1).

Let's find the ordered pairs of the inverse function. We take all the ordered pairs of the original function:

(1, 3), (7, 4), (8, 6), (9, y)

Now we switch x and y in each ordered pair to come up with the inverse function.

The inverse function has these ordered pairs:

(3, 1), (4, 7), (6, 8), (y, 9)

For a relation to be a function, a value used as an x-coordinate can appear only once.

The last ordered pair is (y, 9). For the inverse relation to be a function, y cannot be 3, 4, or 6.

4 0
3 years ago
Read 2 more answers
Pls help me calculate the total area of compound shapes?!?!?
alexandr1967 [171]

Answer:

Number 1 is 38cm and number 2 is 22ft.

5 0
2 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0
2 years ago
1. −5tan 2 θ+3=8tanθ+6<br> 2. 2cosθ-3=5cosθ-5
pychu [463]

Answer

(tan x + 3)=5

Step-by-step explanation:

3 0
3 years ago
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