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Dominik [7]
3 years ago
6

Round each number to the nearest million, thousand, and ten

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0

Answer:

1)

<em> </em><em>a</em><em>.</em><em> </em>4,000,000

<em>b</em><em>.</em><em> </em>4,327,000

<em>c</em><em>.</em><em> </em>4,326,800

2)

<em>a</em><em>.</em><em> </em>30,000,000

<em>b</em><em>.</em> 29,727,000

<em>c</em><em>.</em><em> </em>29,726,520

3)

<em>a</em><em>.</em> 3,000,000

<em> </em><em>b</em><em>.</em><em> </em>2,867,000

<em>c</em><em>.</em> 2,867,000

Step-by-step explanation:

i mean,,

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Given that g(y) = y2 - 1, find g(a - 1).<br>Give your answer in its simplest form.​
AlekseyPX

Answer:

a^2 - 2a.

Step-by-step explanation:

Replace the y in g(y) by a - 1 and simplify.

g(a-1) = (a - 1)^2 - 1

= a^2 - 2a + 1 - 1

= a^2 - 2a.

8 0
3 years ago
Uh, I need help with this question (10 points)
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Step-by-step explanation:

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2 years ago
From their location in the diagram, what are two possible values for m and n?
yarga [219]
M=6/5 and n = sqrt(2), is rational (but not an integer) and n is irrational.

The case with n = sqrt(9)=3, is not a solution. The case with m=4pi neither.

The last case is m = 6/2=3, integer, so neither works.

So, it is the one with m=6/5 and sqrt(2)
3 0
3 years ago
Jason draws a line in the sand at the beach the line is 7/8 feet long he wants to divide the line into sections that are 1 8 fee
abruzzese [7]
The answer is 7 sections
In this type of question, you just need to divide the total length of the line that drawn by Jason with the length of sections that Jason want.

So, the calculation would be:

(7/8) / (1/8)

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Read 2 more answers
Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce
34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)

= 1 - P(z \leq -2)

Calculation the value from standard normal z table, we have,  

P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)

Calculation the value from standard normal z table, we have,  

P(x < 23.7) =0.159= 15.9\%

15.9% of of the boxes weigh less than 23.7 ounces.

7 0
3 years ago
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