Question

I need help ASAP Integrated math II

Answer 1

Answer:

$\boxed{ \bold{ \sf{x = 16}}}$

$\boxed{ \bold{ \sf{m < AFD = 82}}}$

Step-by-step explanation:

$\sf{5x + 18 = 3x + 50}$

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒$\sf{5x - 3x = 50 - 18}$

Collect like terms

⇒$\sf{2x = 50 - 18}$

Subtract 18 from 50

⇒$\sf{2x = 32}$

Divide both sides of the equation by 2

⇒$\sf{ \frac{2x}{2} = \frac{32}{2} }$

Calculate

⇒$\sf{x = 16}$

The value of x is 16

Now, let's find value of m<AFD :

$\sf{m < afd + 5x + 18 = 180}$ ( sum of angle in straight line )

plug the value of x

⇒$\sf{m < AFD + 5 \times 16 + 18 = 180}$

Multiply the numbers

⇒$\sf{m < AFD + 80 + 18 = 180}$

Add the numbers

⇒$\sf{m < AFD + 98 = 180}$

Move constant to R.H.S and change it's sign

⇒$\sf{m < AFD = 180 - 98}$

Subtract 98 from 180

⇒$\sf{m < AFD = 82}$

Value of m<AFD = 82

Hope I helped!

Best regards!!