What are the domain and range of each relation?

What different common denominators is equivalent to seven over eight

uranmaximum [27]

14/16 or 28/32 but can’t be more simplified

5 0

3 years ago

If I lost 4% of 100 pencils an 6% of 200 pens how many pencils do I have left and how many pens do I have left?

DedPeter [7]

To find 4% you multiply 100 by .04
100•.04=4
Then subtract
100-4=96 *you have 96 pencils left*

To find 6% of 200, multiply 200 by .06
200•.06=12
Then subtract
200-12=188 *you have 188 pens left*

6 0

3 years ago

Keith’s Florists has 15 delivery trucks, used mainly to deliver flowers and flower arrangements

vlabodo [156]

Answer:

= 0.419

Step-by-step explanation:

in pic

(Hope this helps can I please have brainlist (crown)☺️)

8 0

3 years ago

patricia says that it's more appropriate to use the method of factoring than extracting square roots in solving 4x2^-9=0. do you

zavuch27 [327]

$1^{o} \\ \\ 4x^{2}-9=0 \\ \\ (2x-3)(2x+3)=0 \\ \\ 2x-3=0 \ \vee \ 2x+3=0 \\ \\ 2x=3 \ \vee \ 2x=-3 \\ \\ x= \frac{3}{2} \ \vee \ x=- \frac{3}{2} \\ \\ 2^{o} \\ \\ 4x^{2}-9=0 \\ \\ 4x^{2}=9 \\ \\ x^{2}= \frac{9}{4} \\ \\ x= \sqrt{ \frac{9}{4} } \ \vee \ -\sqrt{ \frac{9}{4} } \\ \\ x= \frac{3}{2} \ \vee \ x=- \frac{3}{2} \\ \\ 3^{o} \\ \\ 4x^{2}-9=0 \\ \\ \Delta=0^{2}-4*4*(-9)=144 \\ \\ \sqrt{\Delta} =12 \\ \\ x_{1}= \frac{0+12}{8} = \frac{3}{2}$

$x_{2}= \frac{0-12}{8} =- \frac{3}{2}$

8 0

4 years ago

The mean consumption of bottled water by a person in the United States is 28.5 gallons per year. You believe that a person consu

Over [174]

Answer:

$t=\frac{27.8-28.5}{\frac{4.1}{\sqrt{100}}}=-1.707$

$p_v =P(t_{99}$

If we compare the p value with a significance level for example $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, so there is not enough evidence to conclude that the mean for the consumption is less than 28.5 gallons at 0.1 of significance, so we can reject the claim that person consume more than 28.5 gallons.

Step-by-step explanation:

Data given and notation

$\bar X=27.8$ represent the mean for the account balances of a credit company

$s=4.1$ represent the population standard deviation for the sample

$n=1000$ sample size

$\mu_o =28.5$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the mean for the person consume is more than 28.5 gallons, the system of hypothesis would be:

Null hypothesis: $\mu \geq 28.5$

Alternative hypothesis: $\mu < 28.5$

We don't know the population deviation, so for this case we can use the t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{27.8-28.5}{\frac{4.1}{\sqrt{100}}}=-1.707$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$

Since is a one-side lower test the p value would be:

$p_v =P(t_{99}$

In Excel we can use the following formula to find the p value "=T.DIST(-1.707,99)"

Conclusion

If we compare the p value with a significance level for example $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, so there is not enough evidence to conclude that the mean for the consumption is less than 28.5 gallons at 0.1 of significance, so we can reject the claim that person consume more than 28.5 gallons.

5 0

4 years ago