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ipn [44]
2 years ago
13

If I lost 4% of 100 pencils an 6% of 200 pens how many pencils do I have left and how many pens do I have left?

Mathematics
1 answer:
DedPeter [7]2 years ago
6 0
To find 4% you multiply 100 by .04
100•.04=4
Then subtract
100-4=96 *you have 96 pencils left*

To find 6% of 200, multiply 200 by .06
200•.06=12
Then subtract
200-12=188 *you have 188 pens left*
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B.Line graph

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10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

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Normal probability distribution

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Z = \frac{X - \mu}{\sigma}

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In this problem, we have that:

n = 300, p = 0.2

So

\mu = E(X) = np = 300*0.2 = 60

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is P(X \leq 51 + 0.5) = P(X \leq 51.5), which is the pvalue of Z when X = 51.5 So

Z = \frac{X - \mu}{\sigma}

Z = \frac{51.5 - 60}{6.9282}

Z = -1.23

Z = -1.23 has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

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A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 704t
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