A line passes through (3,-2) and (6, 2). Write an equation for the line in point-slope form.
2 answers:
Answer:
see explanation
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (3, - 2) and (x₂, y₂ ) = (6, 2)
m = =
Use either of the 2 points as the point on the line
Using (a, b) = (6, 2), then
y - 2 = (x - 6) ← in point- slope form
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Multiply both sides of the point- slope equation by 3
3y - 6 = 4(x - 6) ← distribute
3y - 6 = 4x - 24 ( subtract 3y from both sides )
- 6 = 4x - 3y - 24 ( add 24 to both sides )
18 = 4x - 3y, that is
4x - 3y = 18 ← in standard form
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