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3 years ago

What Is the quotient 7^-6/7^2 Please help

Mathematics

2 answers:

wel3 years ago

6 0

Answer:

Step-by-step explanation:

When you have $\frac{7^{-6} }{7^{2} }$ , you can see that they have the same base number 7. You can subtract the exponents (top)-(bottom) and keep the base. In order words, you would have -6 - 2 which is -8. Your new answer would be $7^{-8}$ which is equivalent to A.

salantis [7]3 years ago

4 0

Answer:

1/7^8

Step-by-step explanation:

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What is the difference between 480 °C – 60 °C

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Read 2 more answers

Which Question Has roots of x= -2 and x

vazorg [7]

See explanation below.

Explanation:

The 'difference between roots and factors of an equation' is not a straightforward question. Let's define both to establish the link between the two..

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4 0

3 years ago

Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.

Naily [24]

The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube.

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

$V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}$

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3 years ago

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Answer:

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Step-by-step explanation:

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