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seraphim [82]
3 years ago
5

3 equivalent ratios for : 4/3?

Mathematics
1 answer:
lukranit [14]3 years ago
8 0
8/12,12/12,24/30 No mas
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Student made five tetrahedrons, a three dimensional figure with four triangular faces and labeled the faces 1-4. use an equation
JulsSmile [24]
The probability is 1/1024.

Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.

Each tetrahedron roll is independent, since no roll is affected by another.

This means we multiply the probabilities:
1/4(1/4)(1/4)(1/4)(1/4) = 1/1024
3 0
3 years ago
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Are the following lines parallel perpendicular or neither y=-5/3x - 5 and y=4/3x - 5​
katrin [286]

Answer:

neither

Step-by-step explanation:

For lines to be parallels the slopes must be equal, for the lines to be perpendicular the lines have to be inverse reciprocals  meaning if you have a slope of 1/2X then the perpendicular line must be -2X

3 0
2 years ago
AD←→ is tangent to circle M at point D. The measure of ∠DMQ is 58º.
Marat540 [252]

Answer:

32°

Step-by-step explanation:

Given:

∠DMQ = 58º

In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°

Therefore, ∠MDQ = 90°

The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:

180 = ∠DMQ + ∠MDQ + ∠DQM

Solving for ∠DQM, we have:

∠DQM = 180 - ∠DMQ - ∠MDQ

∠DQM = 180 - 90 - 58

∠DQM = 32°

The measure of ∠DQM is 32°

6 0
3 years ago
What is the quotient 2y^-6y-20/4y+12 ÷ y+5y+6/3y^2+28y+27​
malfutka [58]

Answer with explanation:

 \rightarrow \frac{\frac{2y^2-6 y-20}{4 y+12}}{\frac{y^2+5 y+6}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{y^2-3y-10}{2 y+6}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{\frac{(y-5)(y+2)}{2 (y+3)}}{\frac{(y+2)(y+3)}{3 y^2+28 y+27}}\\\\\rightarrow \frac{(y-5)(y+2)}{2 (y+3)}} \times {\frac{3 y^2+28 y+27}{(y+2)(y+3)}}\\\\ \rightarrow\frac{(y-5)\times(3 y^2+28 y+27)}{2 (y+3)^2}}

→y²+5y+6

=y²+3 y+2 y+6

=y×(y+3)+2×(y+3)

=(y+2)(y+3)

→y² -3 y-10

=y² -5 y+2 y -10

=y×(y-5)+2×(y-5)

=(y+2)(y-5)

6 0
3 years ago
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If I got $5 a week how much money would I have after 3 weeks
tensa zangetsu [6.8K]
You would get $15 in total because 5x3=15.
6 0
3 years ago
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