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4 years ago

PLEASE ANSWER AND EXPLAIN, 98 POINTS,

Mathematics

2 answers:

Vitek1552 [10]4 years ago

7 0

The answer would be b.

vodomira [7]4 years ago

3 0

I think it is c but I'm not sure..

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You work in a grocery store warehouse recording shipments. A driver delivers 25 crates of strawberries for distribution. A store

BARSIC [14]

Answer:

18 crates

Step-by-step explanation:

Data provided in the question

The Number of strawberries for distribution delivered is 25 crated

Now he seven crates is required

So the remaining crates left is

= 25 - 7

= 18 crates

hence, after filling the order the number of order crates of strawberries is 18 crates and the same is to be considered

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4 years ago

Line p has an equation of y=4/9x-3. Perpendicular to line p is line q, which passes through the point (3,-8). What is the equati

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If you look on jiskha you will find the answer you will be looking for just type it in B

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4 years ago

A cooler contains 11 cans of soda; 5 colas, 5 orange, and 1 cherry. Two cans are selected at random without replacement. Find th

tino4ka555 [31]

There is a 20.2 percent chance he will get at least one cola

3 0

3 years ago

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What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?

bezimeni [28]

$3\equiv3\mod{20}$
$3^2\equiv9\mod{20}$
$3^3\equiv27\equiv7\mod{20}$
$3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}$

$7\equiv7\mod{20}$
$7^2\equiv49\equiv9\mod{20}$
$7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}$
$7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}$

$9\equiv9\mod{20}$
$9^2\equiv3^4\equiv1\mod{20}$

$11\equiv11\mod{20}$
$11^2\equiv121\equiv1\mod{20}$

$13\equiv-7\equiv13\mod{20}$
$13^2\equiv169\equiv9\mod{20}$
$13^3\equiv13\cdot13^2\equiv(-7)9\equiv-63\equiv-3\mod{20}$
$13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}$

$17\equiv-3\equiv17\mod{20}$
$17^2\equiv(-3)^2\equiv9\mod{20}$
$17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}$
$17^4\equiv(-3)^4\equiv81\equiv1\mod{20}$

$19\equiv-1\equiv19\mod{20}$
$19^2\equiv19(-1)\equiv-19\equiv1\mod{20}$

Generally speaking, a number $x$ coprime to $n$ will be a primitive root of $n$ if we have $x^n\equiv x\mod{n}$ , or $x^{n-1}\equiv1\mod{n}$ . In other words, if $x$ is of order $n-1$ modulo $n$ , then $x$ is a primitive root of $n$ .

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.

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4 years ago

A salesman traveled 736 miles on 32 gallons of gas.How far can be traveled on 128 gallons of gas?

Vanyuwa [196]

2944
736 divided by 32 = 23
23 x 128= 2944

4 0

3 years ago

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