<h3>The time in fourth race is 43.04 seconds</h3>
<em><u>Solution:</u></em>
Given that,
Shelly is trying to improve her running time for a track race
She ran the first race in 43.13 seconds
Her time was 43.1 seconds in the second race and 43.07 seconds in the third race
<em><u>Therefore, pattern is:</u></em>
43.13, 43.1, 43.07 , ..
<em><u>Find the difference between each terms</u></em>
d = 43.13 - 43.1 = 0.03
d = 43.1 - 43.07 = 0.03
Thus the difference is same
<em><u>If this pattern continues what will shellys time be in the fourth race?</u></em>
Fourth race = third race - 0.03
Fourth race = 43.07 - 0.03 = 43.04
Thus the time in fourth race is 43.04 seconds
I hope this helps you find the answer you're looking for
-30m^3-3 here is your answer
7.
If c = 16
that means the equation is
16 - 9
which is 7
so 7
Answer: 56 large cars and 86 small cars.
Step-by-step explanation:
Let's call:
: the number of large cars.
: the number of small cars.
Then, you can set up the following system of equations:
You can use the Elimination Method:
- Multiply the first equation by -4.0
- Add both equations.
- Solve for l.
≈
Substitute 
into one of the original equations and solve for <em>s:</em>
<em> </em>
