There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
Answer:
Not really an answer just warning you didn't actually attach a graph
It would be 6:42 pm I believe.
Answer:
7 and 1
Step-by-step explanation:
Let the numbers be a and b.
<u>A positive number is 7 times another number:</u>
<u>If 3 is added to both the numbers then one of the new number becomes 5 by 2 times the other new number:</u>
<u>To solve this we substitute </u><u>a</u><u> with </u><u>7b</u><u> in the second equation:</u>
- 7b + 3 = 5/2 × (b +3) ⇒ multiplying both sides by 2
- 14b + 6 = 5b + 15 ⇒ collecting like terms
- 14b - 5b = 15 - 6
- 9b = 9
- b = 1 ⇒ solved for b
<u>Then, finding a:</u>
- a= 7b
- a=7*1
- a= 7 ⇒ solved for a
<u>So the numbers are</u> 7 and 1
Answer:
x=2,y=-3
Step-by-step explanation:
detailed explanation showed in the image above
