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Answer:
Step-by-step explanation:
Initial Quantity of salt Q(0) = 100 kg
Capacity of tank = 1000 L
Inflow of liquid = 10 l /minute and outflow = same rate thus leaving the content of volume 1000 L at any time
Assume after entering constantly mixes and drains out.
Concentration flow = inflow - outflow
= 0.05(10) -
i.e. , Q(0) = 100
Use Q(0) = 5
-45 = A
So the equation would be
a) Initial concentratin =
b) Use the solution fo rDE substitute t =1
Q(1) = 50-45e^(-0.01) = 5.4477 kg
c) As t becomes large Q = 50
So concentration limit = 50/1000 = 0.05