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3 years ago

Solve the equation x^2-4x-12=0 two ways. By factoring and by Quadratic formula

1 answer:

8 0

By factoring, find two values j and k which satisfy two conditions, jk=ac=-12 and j+k=b=-4, so j and k must be 2 and -6 so the factors are:

(x+2)(x-6)=0

So x=-2 and 6

By the quadratic formula, x=(-b±√(b^2-4ac))/(2a), in this case:

x=(4±√(16+48))/2

x=(4±√64)/2

x=(4±8)/2

x=2±4

x=-2 and 6

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The scale factor for a model is 5cm= m model: 9.5cm actual : 30.5m

MaRussiya [10]

We are given dimensions of model and actual figure.

model: 9.5cm actual : 30.5m.

We need to find the length of actual shape for the scale factor 5cm.

Let us assume actual length be x m.

Let us set a proportion now.

Let us convert proportion into fractions.

$\frac{5}{x}=\frac{9.5}{30.5}$

On cross multiplying, we get

9.5x = 5× 30.5

9.5x = 152.5.

On dividing both sides by 9.5, we get

$\frac{9.5x}{9.5}=\frac{152.5}{9.5}$

x=16.05.

<h3>Therefore, the scale factor for a model is 5cm= 16.05 m.</h3>

6 0

4 years ago

A one-parameter family of solutions of the de p' = p(1 − p) is given below.

tensa zangetsu [6.8K]

Answer:

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

There is not a solution curve passing through the point(0,1).

Step-by-step explanation:

We have the following solution:

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

Does any solution curve pass through the point (0, 4)?

We have to see if P = 4 when t = 0.

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$4 = \frac{c_{1}}{1 + c_{1}}$

$4 + 4c_{1} = c_{1}$

$c_{1} = -\frac{4}{3}$

A solution curve pass through the point (0,4) when $c_{1} = -\frac{4}{3}$ .

Through the point (0, 1)?

Same thing as above

$P(t) = \frac{c_{1}e^{t}}{1 + c_{1}e^{t}}$

$1 = \frac{c_{1}}{1 + c_{1}}$

$1 + c_{1} = c_{1}$

$0c_{1} = 1$

No solution.

So there is not a solution curve passing through the point(0,1).

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4 years ago

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Crazy boy [7]

Answer:

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3 years ago

I need help with something in school.

Kamila [148]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

The diagonal of a rectangle is 25 in. The width is 15 in. What is the area of the triangle?

Vikki [24]

First, find the length
L^2+W^2=D^2 )L for length, W for width, D for diagonal)
L^2=25^2-15^2=625-225=400
L=20
A=1/2 of L*W= (1/2)*20*15=150 square inches

3 0

4 years ago