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maks197457 [2]
4 years ago
15

Someone help!

Mathematics
1 answer:
DochEvi [55]4 years ago
7 0

Answer:

3 points are:

(0,5.5)\\(-2,4.5)\\(12, 11.5)

Step-by-step explanation:

You might be interested in
6/5 of what number is 60
inn [45]

workings...

60/6=10

10x5=50

answer: 50

3 0
4 years ago
Find the derivative of f(x)= -12x^2+9x
dexar [7]

Answer:

- 24x + 9

Step-by-step explanation:

Differentiate each term using the power rule

\frac{d}{dx} ( ax^{n} ) = nax^{n-1}

Given

f(x) = - 12x² + 9x, then

f'(x) = (2 × - 12)x + (9 × 1) x^{0}= - 24x + 9

3 0
4 years ago
Suppose that a Coke/Pepsi survey was conducted of 40 randomly selected individuals from Gainesville. Thirty people selected Coke
Aleksandr-060686 [28]

Answer:yo

Step-by-step explanation:yo

4 0
3 years ago
A linear function that represents the number of animals adopted from the shelter is compared to a different linear function that
bazaltina [42]

Answer:point slope form

y-y1=m(x-x1)

slope-intercept form

y=mx+b

slope formula

y2-y1/x2-x1

slope of line passing through (3.29,-9.19) & (3.29,4.72)

UNDEFINED

line perpendicular to y=3x-7 & passes through (3,5)

y-5 = -1/3(x-3)

slope of perpendicular lines

negative reciprocals (flip and change signs)

m --> -1/m

covering up method

only used with standard form

-4x + 7y = 56 Find x & y intercepts of equation

x = (-14,0) y = (0,8)

Terry is skiing down a steep hill. Terry's elevation E(t)

in feet after t seconds is given by E(t) = 2000 − 90t.

Write a complete sentence describing Terry's starting elevation and how it is changing over time.

Terry starts at an elevation of 2000 feet and descends at 90 feet per second.

If the graphs of two linear functions are perpendicular, describe the relationship between the slopes and the y-intercepts.

slope: negative reciprocals of one another.  

y-intercept: There is no relationship.

Step-by-step explanation:

6 0
3 years ago
−np − 90 < 30 for n
skelet666 [1.2K]
-np-90+90<30+90
-np<120
-np/-p<120/-p
= n>-120/p
And the answer is = n> -120/p
7 0
4 years ago
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