∫(t = 2 to 3) t^3 dt
= (1/4)t^4 {for t = 2 to 3}
= 65/4.
----
∫(t = 2 to 3) t √(t - 2) dt
= ∫(u = 0 to 1) (u + 2) √u du, letting u = t - 2
= ∫(u = 0 to 1) (u^(3/2) + 2u^(1/2)) du
= [(2/5) u^(5/2) + (4/3) u^(3/2)] {for u = 0 to 1}
= 26/15.
----
For the k-entry, use integration by parts with
u = t, dv = sin(πt) dt
du = 1 dt, v = (-1/π) cos(πt).
So, ∫(t = 2 to 3) t sin(πt) dt
= (-1/π) t cos(πt) {for t = 2 to 3} - ∫(t = 2 to 3) (-1/π) cos(πt) dt
= (-1/π) (3 * -1 - 2 * 1) + [(1/π^2) sin(πt) {for t = 2 to 3}]
= 5/π + 0
= 5/π.
Therefore,
∫(t = 2 to 3) <t^3, t√(t - 2), t sin(πt)> dt = <65/4, 26/15, 5/π>.
<span>3x – 15y = 60
y-intercept x = 0</span>
3(0)– 15y = 60
-15y = 60
y = -4
x-intercept y = 0
3x– 15(0) = 60
3x = 60
x =20
answer :
<span>C. x-intercept: 20; y-intercept: –4</span>
I do not know the full question being asked, but if he reads 3/4 chapters in 4/5 hours, he would read 6/4 chapters, or 1 1/2 chapters in 1 3/5 hours.
Please mark Brainliest if helpful!
If this isn’t your question, please provide it fully in the comments of this answer. :))
20 is the answer.
15% of 50= 7.5
45% of 50= 22.5
22.5+7.5=30
50-30=20.
Answer: -4.96x + 6
Step-by-step explanation:
In this problem, it wants you to multiply the -0.4 by the numbers in the parentheses. Don’t let the X confuse you. This is just a placeholder for an unknown number. So first you would multiply the -0.4 into the 10.2, And once you get your answer, just add the X to the end. Which is -4.08x. Then, you would do the same thing, multiply the -0.4 (the number outside of the parenthesis, only with the -15 now. Which gets you 6. Lastly, you take the -0.4 once more and multiply it by the 2.2x. Which gets you -0.88.
-0.4 (10.2x-15+2.2x)
= - 4.08x +6 -0.88x
Now that you have this problem, combined like terms. What are the like terms in this problem?
The -4.08x can be combined with the -0.88 which gets you -4.96. Bring the +6 down, and that gets you your answer of -4.96 +6.
-4.08x -0.88x +6
= -4.96x +6
This would be your final answer because nothing further can be done at this point.
hope this helps!
