Answer:
The probability that all the five flights are delayed is 0.2073.
Step-by-step explanation:
Let <em>X</em> = number of domestic flights delayed at JFK airport.
The probability of a domestic flight being delayed at the JFK airport is, P (X) = <em>p</em> = 0.27.
A random sample of <em>n</em> = 5 flights are selected at JFK airport.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.
The probability mass function of <em>X</em> is:
Compute the probability that all the five flights are delayed as follows:
Thus, the probability that all the five flights are delayed is 0.2073.
He would have to charge 80 cents per candy bar!
Just multiply both dimensions by 2 to make it into centimeters.
Therefore,
4*2 x 5*2 (in inches) will be:
8cm x 10cm (in centimeters)
We conclude that the dimensions of her postcard into a graphic on her web page will be 8x10 in centimeter units.
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Answer:
V= 14.13
Step-by-step explanation:
Information needed:
V= 4/3
r^3
= 3.14
r= 3/2
Solve:
V= 4/3r^3
V= 4/3(3.14)(3/2)^3
V= 4/3(3.14)(27/8)
V= 14.13
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
