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const2013 [10]
3 years ago
13

A particle moves with velocity function v(t) = 2t^2 - 3t - 3, with v measured in feet per second and t measured in seconds. Find

the acceleration of the particle at time t = 2 seconds.
Mathematics
1 answer:
SashulF [63]3 years ago
3 0
V(t) = 2t^2 - 3t - 3

for an acceleration a(t),
a(t) = d (v(t)) / d t
a(t) = 4t - 3

at t=2
a(2) = 8 - 3
a(2) = 5 feet/s^2

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Answer:

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Step-by-step explanation:

Finding the Number

To find the number, we have to translate the problem above to an algebraic equation. The algebraic equation refers to the statement of the equality of two algebraic expressions.

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