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alexandr402 [8]
3 years ago
14

A 24-year-old nulliparous woman comes into the office because she has not had her menses for six months. she is in good health a

nd not taking any medications. she is not sexually active. she does well in graduate school, despite her demanding new program. her height is 5 feet 6 inches and her weight is 104 pounds. her vital signs are normal. her physical examination, including a pelvic examination, is completely normal. what is the most likely reason for her amenorrhea?
Biology
1 answer:
liberstina [14]3 years ago
7 0
She might have a deficiency of iron in her body which could affect her menstruation. She might have to change her diet as the dietary maybe poor.
You might be interested in
Which term actually applies to a blend of several different complementary hormones that promote the maturation and functional co
34kurt

Answer:

Thymosin

Explanation:

Thymosin is the term used to refer to a set of thymus polypeptide hormones that influence the maturation of T lymphocytes intended to play an active role in cell mediated immunity. Thymosin may serve as an immunotransmitter by modulating the hypothalamic-pituitary-adrenal and gonadal axes. It also helps to counteract the harmful effects of cortisol.

8 0
3 years ago
An additional gene, gene W, was also examined. A test cross was made between true-breeding EEWW flies and EEWW flies. The result
Debora [2.8K]

This question is incorrect but here is the correct question below;

An additional gene,gene W was also examined. a test cross was made between true breeding EEWW flies and eeww flies. The resulting F₁ generation was then crossed with eeww flies. 100 offspring in the F₂ generation were examined and it was discovered that the E and W genes were not linked.

Which is the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked?

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

b) Linked: 25% Eeww, 50% eeWw; not linked:parental genotypes EeWw and eeww.

c) Linked genotypes (EeWw and eeww) and recombinant genotype ( Eeww & eeWw) in the F₂ generation are nearly the same irrespective of their linkage.

d) Linked: mostly with parental genotypes, Eeww and eeWw; unlinked: 25% EeWw and eeww with 75% Eeww and eeWw.

Answer:

a) Linked: 50% EeWw and 50% eeww; not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

Explanation:

a test cross was made between true breeding EEWW flies and eeww flies

If EEWW self crossed, we have the following ( EW, EW, EW, EW)

Also, for eeww, we have ( ew, ew, ew, ew)

                   

                    EW                   EW                     EW                   EW

ew               EWew               EWew               EWew               EWew      

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

ew               EWew               EWew               EWew               EWew

All offspring are  (EWew)

The question goes further by saying "The resulting F₁ generation was then crossed with eeww flies".

And we are asked to find the correct genotype of the F₂ offspring if the genes were linked and if the genes were not linked

∴

To determine  the offsprings of the linked genes we need to go by the definition and understand what linked genes are: Linked genes are genes that are physically close together on the same chromosomes. Effect of recombinantion on linked genes, results in gene swaps which occur in chromosomes that are homologous.

Having said that; If  EWew × eeww

we have;                 EW   &   ew    ×    ew  &    ew

           EW               ew

ew       EeWw          eeww

ew       EeWw          eeww

offspring that

are linked in   ⇒     EeWw    EeWw     &      eeww      eeww

F₂   will be

\frac{1}{2} = 50% of EeWw of the total 100 offspring in the F₂ cross

\frac{1}{2} = 50% of eeww of the total 100 offspring in the F₂ cross

∴ Linked genes =  50% EeWw and 50% eeww.

For unlinked genes; If  EWew × eeww

if rearrangement occurs in EWew  and EWew self crossed, we have ( EW,Ew,eW,ew) as the traits needed for the unlinked gene F₂ crossing.

Also ewew will be (ew, ew, ew, ew).

                       EW                    Ew                    eW                    ew

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw               Eeww                eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

ew                  EeWw              Eeww                 eeWw                eeww

We have the following results for the unlinked genes

\frac{1}{4} = EeWw  25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = Eeww   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeWw   25% of the total 100 offspring in the F₂ cross

\frac{1}{4} = eeww    25% of the total 100 offspring in the F₂ cross

∴ not linked: 25% EeWw, 25% Eeww, 25% eeWw and 25% eeww.

3 0
3 years ago
Which features set most of the members of protista apart from the rest of the kingdoms
Colt1911 [192]

Answer: Unicellular and microscopic features set the protista apart from the rest of the kingdom.

Explanation:

Protista are eukaryotic organisms that are neither plants, animals or fungi. They do not have a natural group with whom they share common ancestor. They have a unique features that set them apart from the rest of the kingdom which are unicellular and microscopic. Examples are amoeba, blue green algae, diatoms, green algae, ciliates and many more.

8 0
3 years ago
Read 2 more answers
Several tissues make up a ?
azamat
Skin muscle etc.yk look it up too :()
8 0
3 years ago
A capsule stain is described as a negative stain because the capsule itself __________. does not take up stain has a negative ch
KonstantinChe [14]

Answer:

Does not take up the stain.

Explanation:

Negative staining refers to the process wherein the unstained specimen is visualized under the darkly stained background.

One of the examples is capsule staining wherein the capsulated cells are stained with India ink or nigrosin dyes. The particles of these dyes stain the background blue-black but cannot enter the capsule.

Hence, the light-colored capsulated cells are visualized in the midst of the blue-black background.

6 0
3 years ago
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