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kumpel [21]
3 years ago
12

There are 180 people at Mary Ellen’s wedding. She pays $32.50 for food for each child and $67 for food for each adult. The total

cost for food for the reception was $10,818.
Mathematics
1 answer:
worty [1.4K]3 years ago
7 0
Dont really know what the question is but,,


there are around 30 adults and 31 children. 
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gtnhenbr [62]
The first question asks who sold more rolls. So start with figuring out how many Christie sold.
5 total - 1 2/3 left = 3 1/3 sold
you can convert the numbers to improper fractions with the same denominator. Like this:
5 x (3/3) - (3+2)/3
15/3 - 5/3 = 10/3
10/3 = 3 1/3

So now we know Christie sold more because 3 1/3 dozen is more than 2 1/2 dozen.

The part asks how many more.. Subtract the amounts the two girls sold.

3 1/3 - 2 1/2
10/3 x (2/2) - 5/2 x (3/3)
20/6 - 15/6 = 5/6

Christie sold 5/6 dozen more rolls. A dozen is 12 rolls so if you wanted to go further you just multiply 12 x 5/6 = 10 rolls
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3 years ago
Of the following numbers, which one is prime: 32, 42, 29, 15?
SVETLANKA909090 [29]
The answer is 29 I think
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What is the volume of this square pyramid? 384 cm³ 288 cm³ 192 cm³ 96 cm³ A square pyramid with height of eight centimeters, bas
Butoxors [25]

Answer:

Its 384 cm

Step-by-step explanation:

I took the quiz

6 0
2 years ago
Solve the system. x+12y=68 x=8y-12
julsineya [31]
X+12y=68
x=8y-12

(8y-12) +12y=68
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4 years ago
The measurement of the height of 600 students of a college is normally distributed with a mean of
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Answer: Second Option

P(180

We know that the mean is:

\mu=175

and the standard deviation is:

\sigma=5

We are looking at the percentage of students between 180 centimeters and 185 centimeters in height.

This is:

P(180

We calculate the Z-score using the formula:

Z=\frac{X-\mu}{\sigma}

For X=180

Z_{180}=\frac{180-175}{5}

Z_{180}=1

For X=185

Z_{185}=\frac{185-175}{5}

Z_{185}=2

Then we look at the normal table

P(1

P(1

P(1

P(1

P(180

Note: You can get the same conclusion using the empirical rule

Look at the attached image for \mu+ 1\sigma

6 0
4 years ago
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