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4 years ago

A line perpendicular to the line y=1/2x+5 with y-intercept -2

1 answer:

3 0

Y = 1/2x + 5...slope here is 1/2. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So our perpendicular slope is -2/1 or just -2 (see how I flipped the slope and changed the sign)

y = mx + b
slope(m) = -2
y int (b) = -2

so ur equation is : y = -2x - 2

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Determine which point is the solution to the given system. y= -7/2 x + 32 y= 4/5 x -11

taurus [48]

Answer:

(10, -3)

Step-by-step explanation:

$-\frac{7}{2}x+32=\frac{4}{5}x-11 \\ \\ -35x+320=8x-110 \\ \\ -43x=-430 \\ \\ x=10 \\ \\ \therefore y=-\frac{7}{2}(10)+32=-3$

7 0

1 year ago

Shane has 1/2 pound of cheese to make 4 sandwiches. He wants to use the same amount of cheese in each sandwich. What fraction of

anastassius [24]

Answer:

The fraction of one pound of cheese to be used in each sandwich is 1/8

Step-by-step explanation:

Here, we have a question that requires the method of dealing with the division of fractions.

To divide a fraction by a whole number, we multiply the denominator of the fraction by the whole number as follows;

$\frac{x}{y} \div z =\frac{x}{y\times z}$

Quantity of cheese Shane has = 1/2 pound

Number of sandwiches to be made = 4

Amount of cheese per sandwich = 1/2÷4 = 1/8.

6 0

4 years ago

On a typical long distance call you talk for 30 minutes. On a typical local call you talk for 10 minutes. Your phone company off

klio [65]

The number of long distance calls to be made can be obtained by linear programming

To minimize the phone bill, the number of long distance call to be made is none

Reason:

Maximum number of number of long distance calls = 15

Maximum number of local calls = 30

Number of minutes of calls to make each month = 240 minutes

Duration of each long distance call = 30 minutes

Duration of each local call = 10 minutes

Cost of long distance call = $0.08

Cost of local call = $0.03

Solution:

Let X, represent the number of long distance calls, and let Y represent the number local calls

The objective function is given as follows;

P = 0.08·(30)·X + 0.03·(10)·Y

P = 2.4·X + 0.3·Y

The constraints are;

X ≥ 0

Y ≥ 0

X ≤ 15

Y ≤ 30

30·X + 10·Y ≥ 240

Solving we have;

Y ≥ 24 - 3·X

The above inequality can be plotted with MS Excel

From the objective function, P = 2.4·X + 0.3·Y, the coefficient of the long

distance calls, X is larger than the coefficient of the local calls Y, therefore,

making the minimum possible number of long distance calls of 0, and 24

local calls will give a cost;

P = 2.4 × 0 + 0.3 × 24 = 7.2

Therefore, to minimize the phone bill, the number of long distance calls to

be made is zero long distance calls

Learn more about linear optimization here:

brainly.com/question/21491539

5 0

3 years ago

Calculate the distance between the points (-8,1) and (0,7)

guapka [62]

Answer:

10 units

Step-by-step explanation:

$\boxed{distance = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }}$

Using the distance formula above,

distance between the 2 points

$= \sqrt{[0 - ( - 8)]^{2} + (7 - 1)^{2} } \\ = \sqrt{(0 + 8)^{2} + 6^{2} } \\ = \sqrt{ {8}^{2} + 36} \\ = \sqrt{64 + 36} \\ = \sqrt{100} \\ = 10 \: units$

8 0

4 years ago

What are 86.98 times 348.088 divided by 1,159,053

nadya68 [22]

0.02/ zero point zero two

4 0

3 years ago