From least to greatest is square root of 3, square root of 5, 22/7 , 16/4
hope it help
Answer:
B=9
Step-by-step explanation:
b+4=2b-5
b-2b+4=-5
b-2b=-5-4
-b=-5-4
-b=-9
b=9
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Since x+y equals 5 that means x is 3 and y is 2 because 3+2=5. So now plug it in, 2(3)+3(2). Two multiplied by three is 6 and three times two is 6. So now it’s 6+6 which equals 12. So it’s 2(3)+3(2)=12
